1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tanzania [10]
2 years ago
7

The magnitude of vector λa is 5. Find the value of λ, if: a = (−6, 8)

Physics
1 answer:
Nata [24]2 years ago
4 0

Given :

\:  \:

  • \color{pink}{\rm \: The \:magnitude \:of \:vector\: λa\: is \:  {\bold5\:}}

\:

  • \color{green}{\rm \: a = (−6, 8)}

\:

To Find :

\:  \:

  • \orange{ \rm\: value \:  of \:  \bold{ λ \: }}

\:  \:

\rm \: The \:  magnitude \:  of \:  the  \: vector  \: a  \: is  \:  ||a|| = \sqrt{(-6)^2+ 8^2)}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:  \:  \rm = \sqrt{( 36+64)} \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:\:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:\:\:   \: \:\:= \rm\sqrt{100} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: \:  \:  \:   \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:\\\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:\: \rm   \underline{\boxed{\red{ \:  = 10 \: }}} \green✓

\:  \:

\rm \: Therefore, \:  λ =   \cancel{\frac{5}{10} } \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \underline  {  \: \boxed{ \red{\: \rm = 0.5\:}}}{  \green ✓ }

Hope helps ~

\color{purple}\frak{SarcasticSmileeᥫ᭡}

`

You might be interested in
As an object fall in a gravitational field, its speed increases. This is an example of potential energy transforming into what?
IrinaK [193]

Answer:

potential energy is transformed into kinetic energy

5 0
3 years ago
.prove : s=ut +½ at²​
o-na [289]

Explanation:

Let the distance covered by the body be s, initial and final velocities be u and v respectively and time taken be t.

\therefore Average\: velocity = \frac{u+v}{2} \\\\Now, \:we \:know\: that\\\\Distance \:covered\\ = Average\: velocity \times time\\\\\therefore s= \frac{(u+v) }{2} \times t..... (1)\\\\

By first equation of motion:

v = u + at

Substituting the value of v in equation (1), we find:

s= \frac{(u+u + at)}{2} \times t\\\\\therefore s= \frac{(2u + at)}{2} \times t\\\\\therefore s= \frac{(2ut + at^2)}{2}\\\\\therefore s=  \frac{2ut} {2}+ \frac{at^2}{2}\\\\   \huge \orange {\boxed {\therefore s= ut+ \frac{1}{2}at^2}} \\\\

Hence proved.

6 0
3 years ago
An athlete swings a 5.00-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.800 m at an angular s
Thepotemich [5.8K]

Answer:

1kg is the answer i think

7 0
2 years ago
how would your weight change with time if you were on s space ship traveling away from Earth toward the moon
astra-53 [7]

Well, before we discuss that, I think we have to carefully understand
and agree on something.  We have to be very clear about what we
mean by 'weight' ...  is it what you feel, or is it the product of

           (your mass) x (the acceleration of gravity where you are).

If you're on a space ship, then any time your engine is not burning,
you feel weightless.  It doesn't matter where you are, or what body
you may be near.  If you're not doing a burn, and the only force on
you is the force of gravity, then you don't feel any weight at all.

But of we say that your 'weight' is the product of

           (your mass) times (the acceleration of gravity where you are),

then it depends on where you are, and whether you're close to
the Earth or closer to the moon.  You may not feel it, but you're
going to have weight, and it's going to change during your trip
in space.

You know that the force of gravity depends on how far you are
from the body that's attracting you.

-- As you travel from the Earth to the moon, gravity will pull you
less and less toward Earth, and more and more toward the moon. 

-- Your weight will get less and less, until you reach the point
in space where the gravitational attractions are equal in both
directions.  That's about 24,000 miles before you reach the
moon ... about 90% of the way there.  At that point, your weight
is really zero, because the pull toward the Earth and the pull toward
the moon are equal.

-- From there, the rest of the way to the moon, your weight will
start to grow again.  It begins at zero at the 'magic point', and it
grows and grows until you reach the moon's surface.  When
you're there, your weight has grown to about 1/6 of what you
weigh on Earth, and it won't get any bigger.  If you weigh
120 pounds on Earth, then you weigh about 19.86 pounds on
the moon ... PLUS your space suit, boots, heater/air conditioner,
oxygen tank, radiation shielding, radio, and all the other stuff that
you need to survive on the moon for a few hours.
8 0
3 years ago
Free fall the object with less air resistance falls with a greater acceleration true or false
Nikitich [7]
False is the correct answer
6 0
3 years ago
Other questions:
  • Explain 5 things that could cause an incorrect mass when using the triple bean balance?
    15·2 answers
  • How did France and Spain use what they learned during the American revolution to benefit their own countries
    10·1 answer
  • Which of the following electromagnetic waves is not used for communication?
    8·1 answer
  • Electromagnetic waves differ fundamentally from either water or sound waves because they
    9·1 answer
  • A circular saw blade with radius 0.175 m starts from rest and turns in a vertical plane with a constant angular acceleration of
    14·1 answer
  • if a ball on a string swung in a circles and string suddenly breaks.the ball will move into what direction?
    6·1 answer
  • Pertaining to simple machines and levers what changes when the fulcrum position is modified
    12·1 answer
  • How does energy travel? Where is the initial source of enenergy in our solar system? What is the process that gives off energy f
    13·1 answer
  • What is the main limitation of debye huckel theory​
    6·1 answer
  • Need help with a physics question.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!