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Ierofanga [76]
3 years ago
12

5. Put these in order from least to greatest resistance:

Physics
1 answer:
zloy xaker [14]3 years ago
8 0
<span>superconductors, conductors, semiconductors, insulators </span>
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Assume: The bullet penetrates into the block and stops due to its friction with the block. The compound system of the block plus
tino4ka555 [31]

Answer:

1)4.7334J

2)225.4m/s

Explanation:

v= the Velocity of both the bullet and the block after collision=?

H= Height of the bullet along circular arc= 10cm=0.1m

g= acceleration due to gravity= 9.81m/s^2

R= Radius of the circular arc= 18cm= 0.18m

m= Mass of the bullet= 30g= 0.03kg

M= Mass of the block = 4.8 kg

Using the law of conservation of energy

Potential energy of the system= Kinectic energy of the system

1/2 mv^2= mgh..............eqn(1)

But we have two mass m and M

We can write eqn(1) as

0.5(m+M)v^2= (m+M)gh ...........eqn(2)

If we make "v" subject of the formula we have

v = √2gh

Then substitute the values we have

= √2 x 9.81 x 0.1 = 1.40m/s

1) We can now calculate the total energy of the system after collision as

KE = 1/2(m+M)v^2

= 1/2 x (0.03+4.8) x (1.40)^2

KE = 4.7334J

Hence, the total energy of the composite system at any time after the collision is 4.7334J

2)to determine the initial velocity of the bullet.

From law of momentum conservation, which can be expressed as

m1u1+m2u2=(m1+m2)v

Where the initial Velocity of the bullet u1= ?

Final velocity of the bullet = 0

the Velocity of both the bullet and the block after collision=v= 1.40m/s

(0.03×u1) +(u×0)= (4.8+0.03)1.4

0.03u1=6.762

U1=225.4m/s

Hence, the initial velocity of the bullet is 225.4m/s

3 0
3 years ago
A speaker vibrates at a frequency of 200 hz what is its period
Norma-Jean [14]

Period = (1) / (frequency)

Period = (1) / (200 per second)  =  0.005 second  =  5 milliseconds

5 0
3 years ago
Read 2 more answers
A person standing on a scale feels a normal force of 655 N pushing up on him. What is his mass?
Dahasolnce [82]
I’m pretty sure the answer would be 66.79141 kilogram force
5 0
3 years ago
A moving electric charge is surrounded by:
kaheart [24]

Answer:

both an electric field and a magnetic field

Explanation:

5 0
3 years ago
The horizontal surface on which the block slides is frictionless.The speed of the block before it touches the spring is 6.0 m/s.
Aloiza [94]

Answer:

V = 5.4 m/s

Explanation:

It is given that,

Let mass of the block, m = 10 kg

Spring constant of the spring, k = 2 kN/m = 2000 N/m

Speed of the block, v = 6 m/s

Compression in the spring, x = 15 cm = 0.15 m

Let V is the speed of the block moving at the instant the spring has been compressed 15 cm. It can be calculated using the conservation of energy of spring mass system.

\dfrac{1}{2}m^2=\dfrac{1}{2}kx^2+\dfrac{1}{2}mV^2

mv^2=kx^2+mV^2

V^2=\dfrac{mv^2-kx^2}{m}

V^2=\dfrac{10\times 6^2-2000\times (0.15)^2}{10}

V = 5.61 m/s

From the given options,

V = 5.4 m/s

Hence, this is the required solution.

3 0
3 years ago
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