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Sidana [21]
1 year ago
11

deidre walked her dog a distance of 95 meters to the north. the walk took 45 seconds. what was their velocity

Physics
1 answer:
dezoksy [38]1 year ago
6 0

Velocity of Deidre and her dog is 2.11m/s.

<h3>What is velocity?</h3>
  • Velocity is the rate of change of position of an object in a particular frame of reference
  • Mathematically, velocity of an object = Displacement of the object/time taken

<h3>What is velocity of Deidre and her dog ?</h3>
  • The distance covered by Deidre and her dog is 95 meter towards north.
  • The time taken to cover the distance is 45 second.
  • So velocity of Deidre and her dog =95/45

=2.11m/s

Thus , we can conclude that the velocity of Deidre and her dog is 2.11 m/s towards north .

Learn more about velocity here :

brainly.com/question/80295?source=archive

#SPJ1

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How many atoms are in 3MgCl2?
Bogdan [553]

Answer:

3MgCl2 has 9 atoms.

Explanation:

The Element Magnesium (Mg) has 3 atoms.

The Element Chloride (Cl) has 6 attoms.

Their fore 6 + 3 is 9 of course. 3MgCl2 has 9 atoms.

BTW: 3MgCl2 is a molecular compound as well as H2O and CO2.

8 0
2 years ago
An elevator has a mass of 1000 Kg. What force is needed to accelerate it upward at a rate of 2 m/s/s?
zubka84 [21]

The force needed to accelerate an elevator upward at a rate of 2 m / s^{2} is 2000 N or 2 kN.

<u>Explanation: </u>

As per Newton's second law of motion, an object's acceleration is directly proportional to the external unbalanced force acting on it and inversely proportional to the mass of the object.

As the object given here is an elevator with mass 1000 kg and the acceleration is given as 2 m / s^{2}, the force needed to accelerate it can be obtained by taking the product of mass and acceleration.

                  \text {Force}=\text {Mass} \times \text {Acceleration}

                  \text { Force }=1000 \times 2=2000 \mathrm{N}=2 \text { kilo Newon }

So 2000 N or 2 kN amount of force is needed to accelerate the elevator upward at a rate of 2 m / s^{2}.

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3 years ago
Sound waves are classified as which type of wave?answer
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4 0
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Scientific notation of 86400
Mandarinka [93]
8.64×10^4

this is 86400 in scientific notation

3 0
3 years ago
Read 2 more answers
What is the strength of the electric field 0.1 mmmm below the center of the bottom surface of the plate
Aleksandr [31]

Complete Question

A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?

Answer:

The  values is  E =248.2 \  N/C

Explanation:

From the question we are told that

   The  diameter is  d =  12 \  cm  =  0.12 \ m

    The charge  is  Q =  4.4 nC  =  4.4 *10^{-9} \  C

    The  distance from the center  is  k =  0.1 \ mm   =  1*10^{-4} \  m

Generally the radius is mathematically represented as

        r =  \frac{d}{2}

=>     r =  \frac{0.12}{2}

=>       r =  0.06 \  m

Generally electric field is mathematically represented as  

       E =  \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 +  k^2 } } ]

substituting values  

      E =  \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 +  (1.0*10^{-4})^2 } } ]

     E =248.2 \  N/C

4 0
3 years ago
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