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Sidana [21]
1 year ago
11

deidre walked her dog a distance of 95 meters to the north. the walk took 45 seconds. what was their velocity

Physics
1 answer:
dezoksy [38]1 year ago
6 0

Velocity of Deidre and her dog is 2.11m/s.

<h3>What is velocity?</h3>
  • Velocity is the rate of change of position of an object in a particular frame of reference
  • Mathematically, velocity of an object = Displacement of the object/time taken

<h3>What is velocity of Deidre and her dog ?</h3>
  • The distance covered by Deidre and her dog is 95 meter towards north.
  • The time taken to cover the distance is 45 second.
  • So velocity of Deidre and her dog =95/45

=2.11m/s

Thus , we can conclude that the velocity of Deidre and her dog is 2.11 m/s towards north .

Learn more about velocity here :

brainly.com/question/80295?source=archive

#SPJ1

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The y-axis of this graph IS speed. So the height of a point on the line is speed. If the line is going up or down, then speed is changing.

Sections a, c, and d are all going up or down. Section b is the only one where speed is not changing. So we can't be sure about b, because we don't know if the track may be curving ... the graph can't tell us that. But a, c, and d are DEFINITELY showing acceleration.

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3 years ago
A student gives a brief push to a block of dry ice. A moment later, the block moves across a very smooth surface at a constant s
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Hey There,

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7 0
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2 years ago
A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar
notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2>\omega = 0.23 rad/s</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

L_i = L_f

now we can say

m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega

so we will have

0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega

\omega = 0.23 rad/s

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0
3 years ago
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mart [117]

Answer:

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5 0
2 years ago
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