Answer:
The correct answer is 17 meq/g
Explanation:
Ion exchange capacity (IEC) express the total of active sites of a resin in which ions are attached because the greater molecular weight.
The exchange Reaction can be represented as
R-H
The IEC value (in meq/g) is determinated by using the next equation:
IEC=[(mL of NaOH)*(M of NaOH)]/mass of resin
IEC [(17 mL)*(0.5 M)/0.5]= 17 meq/g
Plasma, Gas, Water, Solid
Answer:
A. 0.0655 mol/L.
B. PbBr2.
C. Pb2+(aq) + Br- --> PbBr2(s).
Explanation:
Balanced equation of the reaction:
Pb(NO3)2(aq) + 2NaBr(aq) --> PbBr2(s) + 2NaNO3(aq)
A.
Number of moles
PbBr2
Molar mass = 207 + (80*2)
= 367 g/mol.
Moles = mass/molar mass
= 3.006/367
= 0.00819 mol.
Since 2 moles of NaBr reacted to form 1 mole of PbBr2. Therefore, moles of NaBr = 2*0.00819
= 0.01638 moles of NaBr.
Since, the ionic equation is
NaBr(aq) --> Na+(aq) + Br-(aq)
Since 1 moles of NaBr dissociation in solution to give 1 mole of Br-
Therefore, molar concentration of Br-
= 0.0164/0.25 L
= 0.0655 mol/L.
B.
PbBr2
C.
Pb(NO3)2(aq)--> Pb2+(aq) + 2No3^2-(aq)
2NaBr(aq) --> 2Na+(aq) + 2Br-(aq)
Net ionic equation:
Pb2+(aq) + 2Br- --> PbBr2(s)
Answer:
4.22 mol H₂O
Explanation:
Step 1: Write the equation for the synthesis of water
2 H₂ + O₂ ⇒ 2 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to H₂O is 1:2.
Step 3: Calculate the moles of water produced from 2.11 moles of oxygen
We will use the previously established molar ratio.
2.11 mol O₂ × 2 mol H₂O/1 mol O₂ = 4.22 mol H₂O
