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irga5000 [103]
1 year ago
7

During the procedure, several wases with cold methanol were done. why was it important to use cold methanol? (In nitration of me

thyl benzoate)
Chemistry
1 answer:
pantera1 [17]1 year ago
3 0

The use of cold methanol is important because it is used to recrystallize or solidify the product.

Since, ice bath is also used in nitration of methyl benzoate because in this reaction the concentrated acid like sulfuric acid is used with water and it is very exothermic.

The formation pure solid from the impure solid compound by mixing with hot solvent and form saturated solution. Now, this solution as cools and pure crystal grows when solubility of the compound decreases. This whole process is called re-crystallization.

learn about re-crystallization

brainly.com/question/14918321

#SPJ4

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Answer :

(a) The moles of water produced are 145.35 moles.

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The balanced chemical reaction is,

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

From the balanced reaction we conclude that

As, 2 moles of C_8H_{18} react to give 18 moles of H_2O

So, 16.15 moles of C_8H_{18} react to give \frac{16.15}{2}\times 18=145.35 moles of H_2O

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<u>Solution for part (b) : Given,</u>

Mass of C_8H_{18} = 878 g

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First we have to calculate the moles of C_8H_{18}.

\text{ Moles of }C_8H_{18}=\frac{\text{ Mass of }C_8H_{18}}{\text{ Molar mass of }C_8H_{18}}=\frac{878g}{114g/mole}=7.702moles

Now we have to calculate the moles of O_2

The balanced chemical reaction is,

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

From the balanced reaction we conclude that

As, 2 moles of C_8H_{18} react with 25 moles of O_2

So, 7.702 moles of C_8H_{18} react with \frac{7.702}{2}\times 25=96.275 moles of O_2

Now we have to calculate the mass of O_2.

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(96.275moles)\times (32g/mole)=3080.8g

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Sam buys a package of chips and notices that hydrogenated vegetables oil is one of the ingredients. This ingredient primarily:
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What is the pH of a solution has a hydrogen ion concentration of 6.3 x 10–10 M? Show work
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