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Fofino [41]
2 years ago
11

What is the [OH-] if the [H3O+] is 1 x 10 -6?

Chemistry
1 answer:
Mariulka [41]2 years ago
5 0

The answer is [OH⁻] = 1 x 10⁻⁸.

To find OH⁻, divide the ionic product of water by [H₃O⁺] as :

<u>OH⁻ + H₃O⁺ = H₂O</u>

<u />

  • [OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
  • [OH⁻] = 1 x 10⁻⁸
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