Question

Please help with math

Answer 1

Answer:

2nd option, x > 1.10

Step-by-step explanation:

$7e^{2x}-5 > 58$

Add 5 to both sides,

$7e^{2x}-5+5 > 58 +5\\7e^{2x} > 63$

Divided both sides by 7,

$\frac{7e^{2x}}{7} > \frac{63}{7}$

$e^{2x} > 9$

Apply Exponent Rule,

$2x > 2ln(3)$

$\frac{2x}{2} > \frac{2ln(3)}{2}$

x > ln(3) or x > 1.09861

Learn more about logarithms here: brainly.com/question/12049968