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2 years ago

10

Please help with math

1 answer:

kykrilka [37]2 years ago

5 0

Answer:

2nd option, x > 1.10

Step-by-step explanation:

$7e^{2x}-5 > 58$

Add 5 to both sides,

$7e^{2x}-5+5 > 58 +5\\7e^{2x} > 63$

Divided both sides by 7,

$\frac{7e^{2x}}{7} > \frac{63}{7}$

$e^{2x} > 9$

Apply Exponent Rule,

$2x > 2ln(3)$

$\frac{2x}{2} > \frac{2ln(3)}{2}$

x > ln(3) or x > 1.09861

Learn more about logarithms here: brainly.com/question/12049968

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3 years ago

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3 years ago

Evaluate the function at the indicated values if possible. If an indicated value is not in the domain, say so.

goldfiish [28.3K]

Answer:

f(-7)=0.

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f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

$f(x)=\frac{x+7}{x^2-9}$ is the given function.

We are asked to find:

$f(-7)$

$f(2)$

$f(3)$ .

f(-7) means to replace x in the expression called f with -7:

Evaluate $\frac{x+7}{x^2-9}$ at $x=-7$

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$\frac{0}{40}$

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So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate $\frac{x+7}{x^2-9}$ at $x=2$

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Evaluate $\frac{x+7}{x^2-9}$ at $x=3$

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3 years ago

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3 0

3 years ago

Read 2 more answers

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prohojiy [21]

Answer:

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Step-by-step explanation:

we know that

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Remember that

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substitute

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4 0

3 years ago