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dusya [7]
2 years ago
14

M1 is a spherical mass (25.0 kg) at the origin. M2 is also a spherical mass (10.6 kg) and is located on the x-axis at x = 94.8 m

. At what value of x would a third mass with a 19.0 kg mass experience no net gravitational force due to M1 and M2?
Physics
1 answer:
Nata [24]2 years ago
8 0

The point where m3 experiences a zero net gravitational force due to M1 and m2 is 57.42 m.

<h3>Position of the third mass</h3>

m1<------(x)------> m3 <-----------(94.8 m - x)-------->m2

a point, x, where m3 experiences a zero net gravitational force due to M1 and m2;

Force on m3 due to m1 = Force on m3 due to m2

Gm1m3/d² = Gm2m3/r²

m1/d² = m2/r²

where;

  • d is the distance between m1 and m3 = x
  • r is the distance between m3 and m2 = 94.8 - x

m1/(x²) = m2/(94.8 - x)²

m1(94.8 - x)² = m2x²

(94.8 - x)² = (m2/m1)x²

(94.8 - x)² = (10.6/25)x²

(94.8 - x)² = 0.424x²

(94.8 - x)² = (0.651)²x²

94.8 - x = 0.651x

94.8 = 1.651x

x = 94.8/1.651

x = 57.42 m

Thus, the point where m3 experiences a zero net gravitational force due to M1 and m2 is 57.42 m.

Learn more about gravitational force here: brainly.com/question/72250

#SPJ1

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\frac{4.83598}{c^{\frac{1}{3} } }

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brainly.com/question/4387241

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3 0
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An object 5.Ocm in the length is placed at a distance of 20cm in front of convex mirror
andrew-mc [135]

Answer:

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Height of the image = 5\times\frac{3}{7}=\frac{15}{7}\ cm

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