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barxatty [35]
1 year ago
7

Some people say the risk of hiv transmission from a healthcare provider (doctor, dentist, nurse, technician) is small. true or f

alse? why?
Physics
2 answers:
Ksju [112]1 year ago
7 0

"Some people say the risk of hiv transmission from a healthcare provider  is small."

That statement is True.  Because ...

There is <em>NO</em> statement on which public opinion is unanimous.

It can be something as innocuous as "The sky is blue during the day and rain makes the ground wet.", and you will never get 100% of the people to agree on it.  There will still be some people who say it's True and others who say it's False.

And plus ... In this particular case, we're talking about a public health question.  In today's political and cultural environment, marked by anti-science tendencies, a lot of people think that Science is not being truthful with us, it's all a big conspiracy, we are all being misled, and every individual should have the freedum to decide for himself.  So when it comes to talking about something like the risk of HIV transmission, everybody is his own expert.  Some will say the risk of transmission from a healthcare provider is substantial, and the rest will say it's small.

So the long sentence in the question is True.  Some people do indeed say that.  

Natalija [7]1 year ago
4 0

Answer:. True

Explanation:

The risk of becoming infected from contact with an HIV-positive healthcare provider is indeed remote. The Centers for Disease Control and Prevention (CDC) have recommended the use of universal precautions by healthcare providers to minimize the risk of transmitting many infectious diseases, including hepatitis and HIV. The risk of transmission from patient to healthcare provider is far greater than from provider to patient.

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Which type of force will an object move towards?
Makovka662 [10]

Answer:

i think it's weakest

EDIT: It's net. I answered weakest but it was wrong and the correct answer was net. oops

Explanation:

if a strong force is acting on something it will push it away, meaning the object would go towards the weaker force

4 0
2 years ago
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How much pressure is created when you apply a
Alekssandra [29.7K]
Pressure
= Force/Area

Area = π(d^2)/4
= π(0.4^2)/4
=0.126 m2
Pressure
= 50/0.126
= 396.825 Pa
5 0
1 year ago
A child’s toy that is made to shoot ping pong balls consists of a tube, a spring (k = 18 N/m) and a catch for the spring that ca
UkoKoshka [18]

Answer:

The height is 3.1m

Explanation:

Here we have a conservation of energy problem, we have a conversion form eslastic potencial  energy to gravitational potencial energy, so:

E_e=\frac{1}{2}K*x^2\\E_e=\frac{1}{2}18N/m*(9.5*10^{-2}m)^2\\E_e=0.081J

then we have only gravitational potencial energy when the ball is at its maximun height.

E_g=m*g*h

because all the energy was transformed Eg=Ee

h=\frac{0.081J}{9.8m/s^2*m}

searching the web, the mass of a ping pong ball is 2.7 gr in average. so:

h=\frac{0.081J}{9.8m/s^2*(2.7*10^{-3}kg)}\\h=3.1m

6 0
3 years ago
A skydiver of mass 80.0 kg jumps from a slow-moving aircraft and reaches a terminal speed of 50.0 m/s. (a) What is her accelerat
kirill [66]

Answer:

6.22²

Explanation:

Given that

Mass of the skydiver, m = 80 kg

Terminal speed of the skydiver, v(f) = 50 m/s

Speed of the skydiver, v(i) = 30 m/s

Acceleration of the skydiver, a = ?

To solve this, we use the formula

W - k v² = ma, where

W = weight of the skydiver

k = constant

v = speed of the skydiver

m = mass of the skydiver

So, if we substitute the values into it we have

W = mg = 80 * 9.8 = 784 N

784 - k 50² = 80 *0

784 - 2500k = 0

784 = 2500k

k = 0.3136

Now, we use this value of k to find the needed acceleration using the same formula at a speed of 30 m/s

784 - 0.3136 * 30² = 80 * a

784 - 0.3136 * 900 = 80a

784 - 282.24 = 80a

497.76 = 80a

a = 497.76 / 80

a = 6.22 m/s²

Thus, we can conclude that the acceleration when the speed of the skydiver is 30 m/s, is 6.22 m/s²

4 0
3 years ago
A car accelerates uniformly from rest and reaches a speed of 24.3 m/s in 9.1 s. The diameter of a tire is 80.2 cm. Find the numb
BaLLatris [955]

By using first and third equation of motion, the number of revolutions the tire makes during this motion is 43 rev.

ANGULAR MOTION

Since the car accelerate from rest, initial velocity will be zero.

Given that a car accelerates uniformly from rest and reaches a speed of 24.3 m/s in 9.1 s. The following are the given parameters

  • Initial velocity U = 0
  • Final velocity V = 24.3 m/s
  • Time t = 9.1 s

If the diameter of a tire is 80.2 cm, to find the number of revolutions the tire makes during this motion, we must first calculate the distance travelled by the car by using first and third equation of motion of the car.

First equation

V = U + at

Substitute all necessary parameters into the equation.

24.3 = 0 + 9.1a

a = 24.3/9.1

a = 2.67 m/s^{2}

Third Equation of motion

V^{2} = U^{2} + 2aS

Substitute all the necessary parameters

24.3^{2} = 0 + 2 x 2.67 x S

590.49 = 5.34S

S = 590.49 / 5.34

S = 110.58 m.

Given that the diameter of a tire is 80.2 cm,

the radius (r) will be 80.2/2 = 40.1 cm

convert it to meter

r = 40.1/100 = 0.401 m

The Circumference of the tire = 2\pir

Circumference = 2 x 3.143 x 0.401

Circumference = 2.52 m

Assuming no slipping, number of revolutions = 110.58/2.52

Number of revolutions = 43.89 rev.

Number of revolutions = 43 rev.

Therefore, the number of revolutions the tire makes during this motion is 43 rev.

Learn more about circular motion here: brainly.com/question/6860269

4 0
2 years ago
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