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Andrews [41]
1 year ago
11

He wants to increase the energy of emitted electrons . Based on the research of Albert Einstein, what is the best way for him to

do this

Chemistry
1 answer:
pishuonlain [190]1 year ago
8 0

To increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

<h3>What is energy of emitted electron?</h3>

The maximum energy of an emitted electron is equal to the energy of a photon for frequency f (E = hf ), minus the energy required to eject an electron from the metal's surface, also known as work function.

Ee = E - W

<h3>Energy of the emitted electron</h3>

The energy of emitted electrons based on the research of Albert Einstein is given as;

E = hf

where;

  • h is planck's constant
  • f is frequency of incident light on the metal

Thus, to increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

Learn more about energy of electron here: brainly.com/question/11316046

#SPJ1

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An artifact contains one-fourth as much carbon-14 as the atmosphere. how old is the artifact
Nikolay [14]
<h3><u>Answer;</u></h3>

= 11,460 years

<h3><u>Explanation;</u></h3>
  • <em><u>The half life of Carbon-14 is 5,730 years . Half life is the time taken by a radioactive material to decay by half of its original mass.  Therefore, it  would take a time of 5730 years for a sample of 100 g of carbon-14 to decay to 50 grams</u></em>

<em>The initial amount of carbon-14 in this case was 1 whole; thus; </em>

<em>1 → 1/2 →1/4</em>

<em>To contain 1/4 of the value, 2 half-lives have passed. </em>

<em>But, 1 half life = 5,730 years</em>

<em>Therefore; The artifact is is therefore: 2 x 5,730 </em>

<em>          = 11,460 years </em>

4 0
2 years ago
Read 2 more answers
Which pair of dispersed phases and dispersing media can never form a colloid?
lana66690 [7]

Answer:

Option B Liquid and Gas

7 0
3 years ago
The nutritional energy content (in Calories) present in 86g of broccoli with 6g of carbohydrates, 2.6g of protein, and 0.3g of f
asambeis [7]

Answer:

37.1 calories.

Approximately, 37.1 = 40 calories.

Explanation:

So, without mincing words let's dive straight into the solution to the question above.

We are given the following parameters which are going to help in solving this particular Question.

The mass of broccoli = 86g of broccoli, mass of carbohydrates present = 6g of carbohydrates, the mass of protein present = 2.6g of protein and the mass of fat present = 0.3g of fat.

Therefore, the nutritional energy content (in Calories) = (6 × 4) + (2.6 × 4) + (0.3 × 9) = 10.4 + 24 + 2.7 = 37.1

Hence, the nutritional energy content (in Calories) = 37.1 calories.

Approximately, 37.1 = 40 calories.

5 0
2 years ago
Liquid helium boils at –268.93 °C. What is the boiling point of helium on the Kelvin temperature scale?
BARSIC [14]

In order to change celcius to kelvin always add 73 to it leaving you with -195.93

4 0
3 years ago
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How many moles is 2.55 x 10 to the power of 26 atoms of Neon?​
Yakvenalex [24]

Answer:

424 mol

Explanation:

Step 1: Given data

Number of atoms of Neon: 2.55 × 10²⁶ atoms

Step 2: Calculate the number of moles corresponding to 2.55 × 10²⁶ atoms of Neon

In order to convert atoms into moles, we need a conversion factor, which is Avogadro's number: there are 6.02 × 10²³ atoms of Neon in 1 mole of atoms of Neon.

2.55 × 10²⁶ atoms × (1 mol/6.02 × 10²³ atoms) = 424 mol

4 0
3 years ago
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