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konstantin123 [22]
2 years ago
11

The reaction between A2 (two large red spheres) and B2 (two small blue spheres) to produce AB is shown in the diagram. The react

ants contain 4 A 2 molecules and 3 B 2 molecules. The products contain 6 A B molecules. Determine the limiting reactant for the reaction. AB A2 B2 no limting reactant
Chemistry
1 answer:
drek231 [11]2 years ago
3 0

Answer:

B₂

Explanation:

The limiting reactant is always a reactant. You can determine which reactant is limiting by identifying which has the smaller mole-to-mole ratio with the product. This ratio can be found via the coefficients of the balanced reaction.

4 A₂ + 3 B₂ ---> 6 AB

4 moles A₂
------------------  = mole-to-mole ratio A₂/AB
6 moles AB

3 moles B₂
------------------  =  mole-to-mole ratio B₂/AB
6 moles AB

Since the mole-to-mole ratio between B₂ and AB is smaller, B₂ must be the limiting reactant.
                           

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Bases in solution produce what type of ions?
Natali [406]
Bases produce hydroxide ions, while acids produce hydrogen ions. 

Bases have a pH of above 7, and are bitter and slippery. 

Answer: <span>c. hydroxide ions</span>
4 0
2 years ago
How many molecules of BH3 are in 14.32 grams of BH3?
kkurt [141]

Answer:

6.23 x 10^23 molecules

Explanation:

First find the number of moles of BH3 from the information given. We know the amount of grams present and we can find the molar mass which is 13.84.

We know that moles is grams divided by molar mass so we get 14.32/13.84 which is 1.03 moles.

Finally, to figure out the number of molecules, we multiply 1.03 by Avogadro's number which is 6.022x10^23 and we get 6.23x10^23 molecules.

3 0
3 years ago
The following reaction shows the products when sulfuric acid and aluminum hydroxide react.
scoray [572]

Leftover: approximately 11.73 g of sulfuric acid.

<h3>Explanation</h3>

Which reactant is <em>in excess</em>?

The theoretical yield of water from Al(OH)₃ is lower than that from H₂SO₄. As a  result,

  • Al(OH)₃ is the limiting reactant.
  • H₂SO₄ is in excess.

How many <em>moles</em> of H₂SO₄ is consumed?

Balanced equation:

2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O

Each mole of Al(OH)₃ corresponds to 3/2 moles of H₂SO4. The formula mass of Al(OH)₃ is 78.003 g/mol. There are 15 / 78.003 = 0.19230 moles of Al(OH)₃ in the five grams of Al(OH)₃ available. Al(OH)₃ is in excess, meaning that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.

How many <em>grams</em> of H₂SO₄ is consumed?

The molar mass of H₂SO₄ is 98.076 g.mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.076 = 28.289 g.

How many <em>grams</em> of H₂SO₄ is in excess?

40 grams of sulfuric acid H₂SO₄ is available. 28.289 grams is consumed. The remaining 40 - 28.289 = 11.711 g is in excess. That's closest to the first option: 11.73 g of sulfuric acid.

6 0
3 years ago
Which example illustrates public scientific communication?
White raven [17]

Answer:

D. A federal government agency publishes an article in a professional scientific journal detailing technical details of a  new virus.

Explanation:

Public scientific communication is a way used by scientists to make the audience able to understand the basics of science to communicate an informed decision. There are several skills under public scientific communication that include connect with the public, talk to journalists, make science understandable, and understand the audience.

<u>The best way to connect with the audience is to publish an article in a professional scientific journal because mostly journals are peer-reviewed having standard of quality.</u>

A federal government agency informing about a  new virus through an article in a professional scientific journal is the best way of public scientific communication as it will be for a specific audience along with a standard of quality.

Hence, the correct answer is "D".

8 0
3 years ago
For the balanced equation shown below, if the reaction of 0.112 grams of
Alekssandra [29.7K]

Answer:

The answer is 74.5%.

Explanation:

As we know that % yield=  \frac{actual yield}{theoretical yield} x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112H_{2} x   \frac{1 mol H_{2} }{2.016 g of H{2} }    x    \frac{4 mol H_{2}O }{4 mol H_{2} }    x  \frac{18.02 g H_{2}O }{1 mol H_{2}O}   = 1.001 g H_{2}O

Now Step 2

% yield   =  \frac{actual yield}{theoretical yield} x 100% =   \frac{0.745g}{1.001g} = 74.5%

8 0
3 years ago
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