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2 years ago

On your way to work about two hours after sunrise, you notice the moon setting. What phase is it in?

Physics

1 answer:

Naily [24]2 years ago

6 0

The moon setting on your way to work about two hours after sunrise means it is in the gibbous phase.

<h3>What is Gibbous phase?</h3>

This phase of the moon involves its side facing the Earth appearing more than half-lit by the Sun, but is less than fully lit.

This phase occurs few hours after sunrise usually in the early morning which is why it is the most appropriate choice.

Read more about Gibbous phase here brainly.com/question/3729811

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A projectile is launched vertically at 100 m/s. If air resistance can be ignored, at what speed will it return to its initial le

eduard

<h2>Speed with which it return to its initial level is 100 m/s</h2>

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 100 m/s

Acceleration, a = -9.81 m/s²

Final velocity, v = ?

Displacement, s = 0 m

Substituting

v² = u² + 2as

v² = 100² + 2 x -9.81 x 0

v² = 100²

v = ±100 m/s

+100 m/s is initial velocity and -100 m/s is final velocity.

Speed with which it return to its initial level is 100 m/s

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3 years ago

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if a bus has a mass of 5000 kg and a velocity of 10 m/s, what must the velocity of a 1500 kg can be to have the same momentum

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Answer:

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3 years ago

How would the number 13,900 be written using scientific notation?

Oksanka [162]

Answer:

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2 years ago

An infant's toy has a 120 g wooden animal hanging from a spring. If pulled down gently, the animal oscillates up and down with a

Morgarella [4.7K]

Answer:

0.37 m

Explanation:

The angular frequency, ω, of a loaded spring is related to the period, T, by

$\omega = \dfrac{2\pi}{T}$

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

$v = \omega A$

A is the amplitude or maximum displacement from the equilibrium.

$v = \dfrac{2\pi A}{T}$

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

$v = \dfrac{2\times3.142\times0.25\text{ m}}{0.58\text{ s}} = 2.71 \text{ m/s}$

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

$v_f^2 = v_i^2+2ah$