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babymother [125]
3 years ago
11

If a marble is released from a height of 10 m how long would it take for it to hit the ground?

Physics
1 answer:
Bas_tet [7]3 years ago
4 0
Depends how much it weighs
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5. A construction worker on a high-rise building is on a platform suspended between two cables as illustrated below. The constru
Natalka [10]

Answer:

a) Tc = 750 [N]  ;b) See the explanation below.

Explanation:

To solve this problem, we first need a graphical explanation of this, as well as knowing the corresponding questions. Therefore, a search was carried out in google, in the attached image we will find a graphical description of the problem.

b)

The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.

a)

In this way we can find by means of a sum of forces on the y axis equal to zero:

- 850 - 450 + 550 + Tc = 0

Tc = 750 [N]

4 0
3 years ago
6. Jim wishes to push a 100. N wood crate across a wood floor.What is the minimum horizontal force that would be required to sta
sergejj [24]
I want to say the answer is 42N
7 0
3 years ago
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During a neap tide, which phase could the moon be in? select all that apply
snow_lady [41]
Hello,

Here is your answer:

The proper answer to this question is option B "<span>third quarter".

Here is how:

Neap tides are caused when the moon is three thirds full which causes the current to up rise therefore making a neap tide.

Your answer is B.

If you need anymore help feel free to ask me!

Hope this helps!

</span>
4 0
3 years ago
Read 2 more answers
Help
aleksley [76]
A- sulfur oxide
B- carbon monoxide
6 0
4 years ago
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PLS HELP. A flatbed car of a train moves 8 m/s to the east. A jogger runs along to top the flatbed car (which is not very safe)
jonny [76]

Answer:

2 m/s

Explanation: Given that a flatbed car of a train moves 8 m/s to the east. A jogger runs along to top the flatbed car (which is not very safe) with a velocity of 6 m/s to the west.

Since the jogger is moving in an opposite direction to the direction of the train, and velocity is the distance covered in a specific direction, the jogger will be moving at a velocity relative to the velocity of the train.

Velocity = (8 - 6) m/s

Velocity = 2 m/s

Therefore, the jogger will be moving at the speed of 2 m/s

5 0
3 years ago
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