0.025 M will be the resulting concentration
Explanation:
To find the resulting concentration we use the following formula:
initial concentration × initial volume = final concentration × final volume
initial concentration = 0.15 M
initial volume = 2 mL
final concentration = ?
final volume = 10 + 2 = 12 mL
0.15 × 2 = final concentration × 12
final concentration = (0.15 × 2) / 12
final concentration = 0.025 M
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molar concentration
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Answer:
2Zn + PbCl4 → 2ZnCl2 + Pb
N.B: ZnCl2 is zinc chloride
Pb is lead
Explanation:
Zinc has a chemical symbol Zn while lead(IV) chloride has the chemical formula, PbCl4. Combining these two substances in a reaction will give rise to the following:
Zn + PbCl4 → ZnCl2 + Pb
However, this equation is not balanced. To balance the equation, we make sure that the atoms of each element on both sides of the reaction are equal. This is done as follows;
2Zn + PbCl4 → 2ZnCl2 + Pb
N.B: ZnCl2 is zinc chloride
Pb is lead
Answer:
S(s) + O2(g) --> SO2(g)
Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).
Explanation:
The reaction is given as;
Sulfur + oxygen --> Sulphur dioxide
Sulphur = S
Oxygen = O2
Sulfur dioxide = SO2
So we have;
S(s) + O2(g) --> SO2(g)
The crrect option is option A. Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).
Combustion of <span>acetylene :
</span><span>molar ma</span>ss acetylene ( C₂H₂ ) = 26.0 g/mol and CO₂ = 44.0 g/mol
<span>
2 C₂H₂ + 5 O₂ ---> 4 CO₂ + 2 H₂O
</span>
2 moles C₂H₂ --------> 4 moles CO₂
? moles C₂H₂ --------> 1.10 moles CO₂
moles C₂H₂ = 1.10 * 2 / 4
moles C₂H₂ = 0.55 moles of C₂H₂
Mass acetylene:
m = n * mm
m = 0.55 * 26.0
m = 14.3 g
hope this helps!
There would be no more because everything had decrease to 0
