Answer:
The number of moles of Fe in 1.17*10^22 atoms Fe is 0.0194 moles
Explanation:
Step 1: Data given
Number of atoms of Fe = 1.17 * 10^22 atoms
Number of Avogadro = 6.022 *10^23
Step 2: Calculate number of moles Fe
Moles Fe = atoms Fe / number of Avogadro
Moles Fe = 1.17*10^22 atoms / 6.022*10^23 / moles
Moles Fe = 0.0194 moles
The number of moles of Fe in 1.17*10^22 atoms Fe is 0.0194 moles
Answer:
c) H2O and OH−
Explanation:
Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.
When an acid donates a proton, it changes into a base which is known as its conjugate base.
Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.
The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.
Thus, for the reaction,

The base is
and the conjugate acid of the base is
.
Also, The base is
and the conjugate acid of the base is
.
<u>Correct option is :- c) H2O and OH−</u>
List of the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) is below,
Here , we have to list the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) and have to identify the group numbers of these metals.
- Hydrogen H+
- Lithium Li+
- Sodium Na+
- Potassium K+
- Rubidium Rb+
- Cesium Cs+
- Beryllium Be2+
- Magnesium Mg2+
- Calcium Ca2+
- Strontium Sr2+
- Barium Ba2+
- Aluminum Al3+
- Zinc Zn2+
- Scandium Sc3+
- Silver Ag+
Co is stable in both +2 and +3 oxidation state. So it can variable. Li only have +1 charge. So it is invariable from one compound to other.
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Answer:
-4
Explanation:
In 0.0034 the zeros are preceding numberd and after the decimal point.
3)
It has more surface area to react with