CaBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of CaBr2 that dissolves.
CaBr2(s) --> Ca+(aq) + 2 Br⁻(aq)
[Br⁻] = 0.17 mol CaBr2/1L × 2 mol Br⁻ / 1 mol CaBr2 = 0.34 M
The answer to this question is [Br⁻] = 0.34 M
Answer:Because the amount of water vapor in the air increases
Explanation:In humid climates, thunderstorms often cause heavier rain than general wintertime rainfall since moisture content in the air typically is higher in the spring and summer, and since air usually rises at a much more rapid rate within developing thunderstorms than in general winter systems.During very heavy rainfall, where all of the water in the atmosphere is often rained out, the water vapour content governs the amount of rainfall. The higher the humidity the greater the water vapour, and the more rain we're likely to see. HOPE THIS HELPS ^w^
Answer:
Oxygen Doesn't change
However, Li is oxidized (0 to +1), Na is reduced (+1 to 0)
Explanation:
On reactant side, Oxygen has -2 oxidation charge because we know common oxidation states such as oxygen -2, hydrogen +1 etc.
So NaOH, O is -2, H is +1, so Na has to be +1 to equal total charge of compound
In product side, LiOH, again O has to be -2, H is +1, so Li +1 as well..
We see that oxygen oxidation state doesn't change. However, for Li it becomes oxidized going from 0 to +1 whereas, Na is reduced going from +1 to 0.
Explanation:
Radium (atomic number 88) has similar properties to barium and is also in the Group 2 category. However, radium is a radioactive element and is generally under the category of radioisotopes in addition to being an alkaline earth metal, because it is not a stable element.
Answer:
5 × 10^-4 L
Explanation:
The equation of the reaction is;
2KClO3 = 2KCl + 3O2
Number of moles of KClO3 = 13.5g/122.5 g / mol = 0.11 moles
From the stoichiometry of the reaction;
2 moles of KClO3 yields 3 moles of O2
0.11 moles of KClO3 yields 0.11 × 3/2 = 0.165 moles of oxygen gas
From the ideal gas equation;
PV= nRT
P= 85.4 × 10^4 KPa
V=?
n= 0.165
R= 8.314 J K-1 mol-1
T= 40+273 = 313K
V= 0.165 ×8.134 × 313/85.4 × 10^4
V=429.4/85.4 × 10^4
V= 5 × 10^-4 L
