Answer:
The answer to your question is SrCrO₄ + H₂O
Explanation:
Data
H₂CrO₄ + Sr(OH)₂ ⇒
We can notice that this is a Redox reaction or neutralization reaction because the reactants are an acid (H₂CrO₄) and a base (Sr(OH)₂). These reactions are also called double displacement reactions.
In these kind of reactions the products are always a binary or ternary salt and water.
Then, for this reaction,
H₂CrO₄ + Sr(OH)₂ ⇒ SrCrO₄ + H₂O
and 
.
Assuming complete decomposition of both samples,
First compound:
; 
of the first compound would contain
Oxygen and mercury atoms seemingly exist in the first compound at a 
ratio; thus the empirical formula for this compound would be where the subscript "1" is omitted.
Similarly, for the second compound
; 
of the first compound would contain
and therefore the empirical formula
.
Answer:
the atomic particles in the necluse are called ions which are positive and negive charged atoms
Explanation:
