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kolbaska11 [484]

1 year ago

5

Use five different colors to paint the four rectangles A, B, C and D shown in the figure. No two rectangles sharing an edge can

be the same color. How many ways are there to color the rectangles?

1 answer:

GenaCL600 [577]1 year ago

8 0

There are 120 ways to color the 4 rectangles

<h3>How to determine the number of ways?</h3>

The given parameters are:

Paints, n = 5

Rectangles, = 4

The number of ways to color the rectangles is

$Ways = ^nP_r$

This gives

$Ways = ^5P_4$

Apply the permutation formula

$Ways = \frac{5!}{1!}$

Evaluate the expression

Ways = 120

Hence, there are 120 ways to color the 4 rectangles

Read more about permutation at:

brainly.com/question/1216161

#SPJ1

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What is the Volume! ~

Mrrafil [7]

Answer:

<u>108</u>

Step-by-step explanation:

Volume of a Square Pyramid :

V = 1/3 x Base Area x Height

Solving :

V = 1/3 x (6)² x 9
V = 36 x 3
V = <u>108</u> cubic centimeters

6 0

1 year ago

Read 2 more answers

6(x-2)=5x+3x+8 solve for x.

Mnenie [13.5K]

Answer:

x = -10

Step-by-step explanation:

6 • (x - 2) - (8x + 8) = 0

Pulling out like terms :

3.1 Pull out like factors :

-2x - 20 = -2 • (x + 10)

Equation at the end of step 3 :

-2 • (x + 10) = 0

Equations which are never true :

4.1 Solve : -2 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2 Solve : x+10 = 0

Subtract 10 from both sides of the equation :

x = -10

One solution was found :

x = -10

Processing ends successfully

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4 0

2 years ago

Read 2 more answers

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

1 year ago

What is the soulution of the equation 3(2x+5)=3x+4

lakkis [162]

x=- $\frac{11}{3}$

or

x=-3.666666666666666666666666666666666666666666666

8 0

2 years ago

Read 2 more answers

Someone answer this please

lions [1.4K]

Answer:

$1,334.5 \: {cm}^{3}$

Step-by-step explanation:

Height of the cylinder h = 17 cm

Radius of the cylinder r = 5 cm

$V_{cylinder} = \pi {r}^{2} h \\ \\ = 3.14 \times {(5)}^{2} \times 17 \\ \\ = 3.14 \times 25 \times 17 \\ \\V_{cylinder} = 1,334.5 \: {cm}^{3}$

7 0

2 years ago