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makkiz [27]
1 year ago
15

1. You have learned that alkyl iodides may be prepared by SN2 replacement of other leaving groups, or by treatment of alcohols o

r ethers with co centrated hydriodic acid (HI). A milder method for preparation of alkyl iodides from alcohols is shown below:
Chemistry
1 answer:
Ainat [17]1 year ago
6 0

Imidazole's cyclic structure is aromatic and the lone pair present at the N₁ atom available for donation. hence, according to question N₁ is the most basic atom in the structure.

<h3>What is resonating structure?</h3>
  • Two π bonds (between C₂-C₃ and N₁-C₅), as well as one lone pair on N₄, can interact with one another to generate a delocalized π system in the cyclic structure.
  • This delocalization is intriguing since it has the same number of delocalized electrons as benzene—six.
  • As a result, imidazole, like benzene, has a closed, delocalized ring with six π electrons. So, like benzene, it is regarded as an aromatic chemical with resonance stability.
  • N₄ is neutral since it cannot be donated because it needs to use its lone pair to be aromatic.
  • On the other hand, N₁ already forms a π connection, which helps the system become delocalized.
  • N₁ is sp² hybridized and has a trigonal planar basic form. Its lone pair cannot communicate with the delocalized π system since it is pointed away from the cyclic structure.

Know more about Resonating structure

brainly.com/question/8155254

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Calculate the amount of F.A.S required to prepare 1000 ml of 0.1 molar standard solution of F.A.S
RideAnS [48]

Answer:

Preparation and Standardization of 0.1 M Ferrous Ammonium...

Dissolve 40 g of ferrous ammonium sulfate in a previously cooled mixture of 40 ml of sulphuric acid and 200 ml of water.

Dilute with sufficient freshly boiled and cooled water to produce 1000 ml.

Standardize the solution in the following manner.

Explanation:

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3 years ago
How does a difference in 1 pH unit change in terms of H+ concentration? Ex: How does a pH of 3 differ from the pH of 4? Which on
yuradex [85]

Answer:

A difference of 1 would mean there is either x10 more or less depending on where you are starting.

Explanation:

The pH of 3 differs from 4 because the acidity of 3 is 10x higher than that of 4. This is due to how the scientific notation of 3 in relation to pH is 10x^-3 while that of 4 is 10^-4 so in terms of the stronger acid that would be the one with the pH of 3.

6 0
2 years ago
Can someone please help me.
siniylev [52]

Answer:

Sure, with what?

Ps- Just to increase word count

5 0
2 years ago
What two elements are present in the compounds in the last two rows of table 4​
castortr0y [4]

Answer:could u expand on the question

Explanation:

8 0
2 years ago
How many molecules of carbon dioxide are dissolved in 0.550 L of water at 25 °C if the pressure of CO2 above the water is 0.250
Grace [21]

<u>Answer:</u> The number of molecules of carbon dioxide gas are 2.815\times 10^{21}

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.034mol/L.atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = pressure of carbon dioxide gas = 0.250 atm

Putting values in above equation, we get:

C_{CO_2}=0.034mol/L.atm\times 0.250atm\\\\C_{CO_2}=8.5\times 10^{-3}M

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of carbon dioxide = 8.5\times 10^{-5}M

Volume of solution = 0.550 L

Putting values in above equation, we get:

8.5\times 10^{-3}M=\frac{\text{Moles of }CO_2}{0.550L}\\\\\text{Moles of }CO_2=(8.5\times 10^{-3}mol/L\times 0.550L)=4.675\times 10^{-3}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 4.675\times 10^{-3} moles of carbon dioxide will contain = (6.022\times 10^{23}\times 4.675\times 10^{-3})=2.815\times 10^{21} number of molecules

Hence, the number of molecules of carbon dioxide gas are 2.815\times 10^{21}

3 0
3 years ago
Read 2 more answers
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