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krok68 [10]
1 year ago
9

A total electric charge of 4.00 nC is distributed uniformly over the surface of a metal sphere with a radius of 26.0 cm. The pot

ential is zero at a point at infinity.
Physics
1 answer:
nevsk [136]1 year ago
7 0

for what we can get from our side then we will see if they are being made in a letter or something <em>which</em><em> </em><em>is</em><em> </em><em>leading</em><em> </em><em>enormous</em><em> </em><em>growth</em><em> </em><em>in</em><em> </em><em>cities</em><em> </em><em>with</em><em> </em><em>brick</em><em> </em><em>and</em><em> </em><em><u>its</u></em><em><u> </u></em><em><u>own</u></em><em><u> </u></em><em><u>way</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>on</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>market</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>its</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good</u></em><em><u> </u></em><em><u>life</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>us</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>stay</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em>

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Explain why squeezing a plastic mustard bottle forces mustard out to top.
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Two identical peaches, Peach 1 and Peach 2, fall from a cliff at time t=0t=0t, equals, 0 from the same height. Peach 1 is droppe
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A control is something you don't touch/change in a exprement, a constant is the same as the control, the independent is the one the you do vhange, the dependet is the one that you observe/ use your 5 sences with.
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4. A chandelier brightens a ballroom after a waiter moves a switch
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because switch moves after a waiter

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3 years ago
6. A 2-kg ball B is traveling around in a circle of radius r1 = 1 m with a speed (vB)1 = 2 m/s. If the attached cord is pulled d
kipiarov [429]

Answer:

Explanation:

Given that,

Mass of ball m = 2kg

Ball traveling a radius of r1= 1m.

Speed of ball is Vb = 2m/s

Attached cord pulled down at a speed of Vr = 0.5m/s

Final speed V = 4m/s

Let find the transverse component of the final speed using

V² = Vr²+ Vθ²

4² = 0.5² + Vθ²

Vθ² = 4²—0.5²

Vθ² = 15.75

Vθ =√15.75

Vθ = 3.97 m/s.

Using the conservation of angular momentum,

(HA)1 = (HA)2

Mb • Vb • r1 = Mb • Vθ • r2

Mb cancels out

Vb • r1 = Vθ • r2

2 × 1 = 3.97 × r2

r2 = 2/3.97

r2 = 0.504m

The distance r2 to the hole for the ball to reach a maximum speed of 4m/s is 0.504m

The required time,

Using equation of motion

V = ∆r/t

Then,

t = ∆r/Vr

t = (r1—r2) / Vr

t = (1—0.504) / 0.5

t = 0.496/0.5

t = 0.992 second

7 0
3 years ago
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