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OlgaM077 [116]
2 years ago
5

What is the voltage drop across the 10.0 ohm resistor?

Physics
1 answer:
DochEvi [55]2 years ago
7 0

The voltage across all the resistors is the same i.e 120V

Each element of the parallel circuit has the same voltage applied to it. The total current flowing from the source is equal to the sum of the currents across each path. The electric potential difference (V) across each resistor in a parallel circuit is the same. Ohm's law states that I = V / R applies to the current in a resistor. The current will be lowest where the resistance is highest since the V is the same for each resistor. The currents passing through each resistor in a parallel combination have the same voltage across them because of their different resistance values and the laws of Ohms i., If two or more components are connected in parallel, they will be having same difference of potential (voltage) across their ends Parallel circuits are then used as current dividers.


To learn more about Parallel circuits please visit -
brainly.com/question/14997346
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What are the main forms of energy? Define each type
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4 0
4 years ago
Four forces act on bolt A as shown; F1 150N, F2 80N, F3 110N and F4 100N. Determine the magnitude and direction of the resultant
netineya [11]

Complete Question

The  complete question(reference (chegg)) is shown on the first uploaded image

Answer:

The magnitude of the resultant force is  F  =  199.64 \ N

The  direction of the resultant force is  \theta  =  4.1075^o from the horizontal plane

Explanation:

Generally when resolving force, if the force (F )is moving toward the angle then the resolve force will be  Fcos(\theta ) while if the force is  moving away from the angle  then the resolved force is  Fsin (\theta )

Now  from the diagram let resolve the forces to their horizontal component

    So

          \sum F_x  =  150 cos(30) + 100cos(15) -80sin (20)

          \sum F_x  =  199.128 \ N

Now  resolving these force into their vertical component can be mathematically evaluated as

         \sum  F_{y}  =  150 sin(30) - 100sin(15) -110 +80 cos(20)

         \sum  F_{y}  =  14.30

Now the resultant force is mathematically evaluated as

        F  =  \sqrt{F_x^2 + F_y^2}

substituting values

        F  =  \sqrt{199.128^2 + 14.3^2}

        F  =  199.64 \ N

The  direction of the resultant force is  evaluated as

       \theta  =  tan^{-1}[\frac{F_y}{F_x} ]

substituting values

       \theta  =  tan^{-1}[\frac{ 14.3}{199.128} ]

       \theta  =  4.1075^o from the horizontal plane

5 0
4 years ago
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