When water falls on land, there are several different paths that are available for it. It can evaporate back into the atmosphere, go into rivers, streams or lakes, it can sink into the ground so therefore, downward and laterally.
Answer:
HW3 Motion (Ldimension _ obiecL acceleralions) Question rocket on the ground is launched with an acceleration of 40 m/s $ upward. seconds inlo the flight the engine shuts off: Assume there no air resistance. Preliminary questions The acceleraton of the rocket i5 40 mls/5. Do you have t0 then adjust this acceleration wth the acceleration due t0 gravity? When Ihe engine shuts ofl, which molion variable(s) changes and how does change? Calculation What is the maximum height that the rocket reaches? At what time atter launch will tne rocket retum to the ground? Queslion You drive into 120 meter long block Irom the Ielt end at = constant speed of 21 mls_ Alter some Ume. you brake with constant acceleralion 0l 3 msls: You want come (0 slop at Ine right end of the block: How much time (Irom when you enter Ihe block) should you wail belore braking? How far down the block (from the left end) d2 you travel before braking? Question You are rest at stop sign; There another stop sign that is 100 meters away: Your maximum acceleration is mists and You maximum braking acceleration misis How much time do you spend acceleraling? How much time do you spend braking? What is the tolal travel lime? Over how much distance do you accelerate? Over how much distance do you brake? What is the tolal travel distanco?
Explanation:
The angular speed remained constant after twelve turns at 11 rad/s.
Explanation:
As per the Newtons equation of motion, the final velocity can be determined by using the below equation, provided ,the displacement and acceleration with initial velocity is given.
Since, the present case follows circular motion, the displacement will be equal to angular displacement. And the velocity is equal to angular velocity.
As the car revolves complete twelve turns, then the displacement will be zero, since the final position is equal to the initial position.
So,
Thus, the angular speed remained constant after twelve turns at 11 rad/s.
Answer:
it leads to attraction, only because the total energy of the electron is negative. Therefore the electron moves closer to the proton rather than farther from it an attractive force.... Electrons are negatively charged and protons are positively charged.
Answer:
a)
b)
Explanation:
<u>Given:</u>
a) when the initial velocity of the projectile is 0.520 times the escape velocity from the earth.
Let r be the radial distance from the earth's surface Let M be the mass of the Earth and R be the radius of the Earth
Now using conservation of Energy at earths surface and at distance r we have
b) when the Initial kinetic Energy of the projectile is 0.52 times the Kinetic Energy required to escape the Earth
Conservation of Energy we have
