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Maslowich
2 years ago
7

A lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms , what is the average

electric current in the lightning?
Physics
1 answer:
malfutka [58]2 years ago
5 0

The average electric current in the lightning will be 8 × 10^{-17} A

<h3>Why Lightning Conductors on top of a tower ?</h3>

The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.

Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.

one charge = 1.6 × 10^{-19} C

Average current I = Q/t

Where

  • Q = charge = 1.6 × 10^{-19} C
  • t = time = 2ms = 2 × 10^{-3} s
  • I = current = ?

Substitute all the parameters into the formula

I = 1.6 × 10^{-19} C ÷ 2 × 10^{-3}

I = 8 × 10^{-17} A

Therefore, the average electric current in the lightning will be 8 × 10^{-17} A

Learn more about Lightning here: brainly.com/question/3183045

#SPJ1

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Carbon dioxide and water

Explanation:

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The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th
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Answer:

Approximate escape speed = 45.3 km/s

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Escape speed

        v=\sqrt{\frac{2GM}{R}}

Here we have

   Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

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Substituting

    v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 2.3\times 10^{30}}{1.496\times 10^{11}}}=4.53\times 10^4m/s=45.3km/s

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Protons and neutrons grouped in a specific pattern
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determine the pressure exerted on the surface of a submarine cruising 175 ft below the free surface of the sea. assume that the
Alenkasestr [34]

Answer:

92.81 psia.

Explanation:

The density of water by multiplying its specific gravity by the density of sea water.

SG = density of sea water/density of water

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1 kg/m3 = 62.4 lbm/ft^3

= 1.03 * 62.4

= 64.27lbm/ft^3.

The absolute pressure at 175 ft below sea level as this is the location of the submarine.

P = Patm +ρgh

= 14.7 + 64.27 * 32.2 * 175

Converting to pound force square inch,

= 14.7 + 64.27 * (32.2ft/s^2) * (175ft) * (1lbf/32.2lbm⋅ft/s^2) * (1ft^2/144in^2 )

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8 0
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A horizontal compass is placed 21 cm due south from a straight vertical wire carrying a 36 a current downward. in what direction
Anit [1.1K]

 <span>
The needle of a compass will always lies along the magnetic field lines of the earth. 
A magnetic declination at a point on the earth’s surface equal to zero implies that 
the horizontal component of the earth’s magnetic field line at that specific point lies along 
the line of the north-south magnetic poles. </span>

The presence of a current-carrying wire creates an additional <span>
magnetic field that combines with the earth’s magnetic field. Since magnetic 
<span>fields are vector quantities, therefore the magnetic field of the earth and the magnetic field of the vertical wire must be combined vectorially. </span></span>

<span>
Where:</span>

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B2 = magnetic field due to the straight vertical wire along the y-axis

We can calculate for B2 using Amperes Law:

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tan θ = 1.326</span></span>

θ = 53°

<span>
<span>The compass needle points along the direction of 53° west of north.</span></span>

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