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Elena-2011 [213]
3 years ago
9

Calculate the amount of heat released when 27.0 g H2O is cooled from a liquid at 314 K to a solid at 263 K. The melting point of

H2O is 273 K. Other useful information about water is listed below.
Cp,liquid = 4.184 J/(g•K)

Cp,solid = 2.093 J/(g•K)

ΔHfusion = 40.7 kJ/mol
Chemistry
2 answers:
Liula [17]3 years ago
7 0

Answer:

Cool liquid from 314 K to 273 K, freeze liquid at 273 K, and cool solid to 263 K.

Explanation:

answer on edg

lubasha [3.4K]3 years ago
5 0
Cool liquid from 314 K to 273 K, freeze liquid at 273 K, and cool solid to 263 K.
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Answer:

Yes, it is possible.

Explanation:

A diprotic acid is an acid that can release two protons. That's why it is called diprotic.

Monoprotic → Release one proton, for example Formic acid HCOOH

Triprotic → Releases three protons, for example H₃PO₄

Polyprotic → Release many protons, for example EDTA

it is a weak acid.

In the first equilibrum, it release proton, and the second is released in the second equilibrium. So the first equilibrium will have a Ka1

H₂A  +  H₂O  ⇄  H₃O⁺  +  HA⁻                Ka₁

HA⁻  +  H₂O  ⇄  H₃O⁺  +  A⁻²               Ka₂

The HA⁻ will work as an amphoterous because, it can be a base or an acid, according to this:

HA⁻   +  H₂O  ⇄  H₃O⁺   + A⁻²      Ka₂

HA⁻   +  H₂O  ⇄  OH⁻   + H₂A       Kb₂

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