A compound has a percent composition of 81.71% C and 18.29% H. What is the empirical formula of this compound?
1 answer:
Considering the definition of empirical formula, the empirical formula is C₃H₈.
<h3>Definition of empirical formula</h3>The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.
<h3>Empirical formula in this case</h3>In this case, in first place you know the percent composition:
- C: 81.71 %
- H: 18.29%
Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 81.71 grams of carbon and 18.29 grams of hydrogen H.
Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:
- C:
= 6.81 moles
- H:
= 18.29 moles
The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:
- C:
= 1
- H:
= 2.68 ≅
To express this relationship in the form of simple integers, it is necessary to multiply by a simple number to achieve this:
- C: 1×3 =3
- H:≅
×3= 8
Therefore the C: H mole ratio is 3: 8
Finally, the empirical formula is C₃H₈.
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Answer: C) 0.020 m
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in g
Mole fraction of is =
i.e.
moles of
is present in 1 mole of solution.
Moles of solute =
moles of solvent (water) = 1 - = 0.99
weight of solvent =
Molality =
Thus approximate molality of in this solution is 0.020 m