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3 years ago

What are the amplitude's for both waves A and B?

Chemistry

1 answer:

Bad White [126]3 years ago

5 0

Answer:

Wave A= 20m

Wave B= 30m

Explanation:

The amplitude of a wave is the maximum displacement (or height) from its equillibrum position.

The equilibrium position is at 0 meters for both waves.

Thus, amplitude of wave A= 20m

Amplitude of wave B= 30m

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Please help again. Sorry!>♡

Svet_ta [14]

Matter is found every where in the universe and there is never any substance in the universe that is not composed of matter.

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The fact that matter inundates the universe has made the study of matter an unavoidable topic. As such, we can not really be able to point something that is of made up of matter. There can be no such thing!

As long as a thing does exist in the material universe, that thing is made up of matter. Look at yourself for example, matter is spread all across your body. The same occurs in the bodies of every other living thing.

The nonliving things are not also left out as they are equally composed of diverse kinds of matter that exists in the universe.

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2 years ago

Explain how chemists overcome the problem of low yield In industry

mrs_skeptik [129]

High temperature and pressure produce the highest rate of reaction. However, this must be balanced with the high cost of the energy needed to maintain these conditions. Catalysts increase the rate of reaction without affecting the yield. This can help create processes which work well even at lower temperatures.

I hope this helps you.

8 0

4 years ago

Balance the chemical equation using the drop-down options.

ryzh [129]

Answer:

CaC2 + 2H20 ⇋Ca(OH)2 + C2H2

Explanation:

CaC2 + A H20 ---> Ca(OH)2 + A C2H2

This is calcium carbide reacting with water to produce calcium hydroxide and ethyne commonly called acetylene.

Let's now balance the equation.

CaC2 + 2H20 ⇋Ca(OH)2 + C2H2

6 0

3 years ago

In the unit cell of galena, six square faces of equal size each form 90 degree angles with every adjacent face. What type of cry

lbvjy [14]

Answer : The correct option is, Cubic.

Explanation :

As there are seven types of crystal systems which are cubic, tetragonal, orthorhombic, monoclinic, triclinic, rhombohedral and hexagonal.

A unit cell is characterized by the axial length (a, b and c) and axial angle $(\alpha ,\beta ,\gamma )$ parameters which decide the size and shape of the unit cell.

In tetragonal crystal system, $a=b\neq c$ and $\alpha=\beta=\gamma=90^o$

In hexagonal crystal system, $a=b\neq c$ and $\alpha=\beta=90^o,\gamma=120^o$

In triclinic crystal system, $a\neq b\neq c$ and $\alpha\neq \beta\neq \gamma=90^o$

In cubic crystal system, $a=b=c$ and $\alpha=\beta=\gamma=90^o$

Hence, the correct option is, Cubic.

7 0

3 years ago

Which aqueous solution would have the lowest vapor pressure at 25°c 1 M NaCl?

aleksley [76]

The question is incomplete, here is a complete question.

Which aqueous solution would have the lowest vapor pressure at 25°c.

A) 1 M NaCl

B) 1 M $K_3PO_4$

C) 1 M $C_{12}H_{10}O_{11}$

D) 1 M $MgCl_2$

E) 1 M $C_6H_{12}O_6$

Answer : The correct option is, (B) 1 M $K_3PO_4$

Explanation :

According to the relative lowering of vapor pressure, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component of the solution multiplied by the vapor pressure of that component in the pure state.

1 M means that the 1 moles of solute present in 1 liter of solution.

Formula used :

$\frac{\Delta p}{p^o}=i\times X_B$

where,

$p^o$ = vapor pressure of the pure component (water)

$p_s$ = vapor pressure of the solution

$X_B$ = mole fraction of solute

i = Van't Hoff factor

As we know that the vapor pressure depends on the mole fraction of solute and the Van't Hoff factor.

So, the greater the number of particles of solute dissolved the lower the resultant vapor pressure.

(a) The dissociation of 1.0 M $NaCl$ will be,

$NaCl\rightarrow Na^++Cl^-$

So, Van't Hoff factor = Number of solute particles = $Na^++Cl^-$ = 1 + 1 = 2

(b) The dissociation of 1 M $K_3PO_4$ will be,

$K_3PO_4\rightarrow 3K^{+}+PO_4^{3-}$

So, Van't Hoff factor = Number of solute particles = $3K^{+}+PO_4^{3-}$ = 3 + 1 = 4

(c) The dissociation of 1 M $C_{12}H_{10}O_{11}$ is not possible because it is a non-electrolyte solute. So, the Van't Hoff factor will be, 1.

(d) The dissociation of 1.0 M $MgCl_2$ will be,

$MgCl_2\rightarrow Mg^{2+}+2Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Mg^{2+}+2Cl^{-}$ = 1 + 2 = 3

(e) The dissociation of 1 M $C_6H_{12}O_{6}$ is not possible because it is a non-electrolyte solute. So, the Van't Hoff factor will be, 1.

From this we conclude that, 1 M $K_3PO_4$ has the highest Van't Hoff factor which means that the solution will exhibit the lowest vapor pressure.

Hence, the correct option is, (B) 1 M $K_3PO_4$

8 0

3 years ago