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zmey [24]
3 years ago
13

What are the amplitude's for both waves A and B?

Chemistry
1 answer:
Bad White [126]3 years ago
5 0

Answer:

Wave A= 20m

Wave B= 30m

Explanation:

The amplitude of a wave is the maximum displacement (or height) from its equillibrum position.

The equilibrium position is at 0 meters for both waves.

Thus, amplitude of wave A= 20m

Amplitude of wave B= 30m

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Someone please help me with number 5. no idea what it is.
KATRIN_1 [288]
Answer is Sodium Hydroxide.
5 0
3 years ago
Calculate hydrochloric acid (umol)in 200 ul of a<br> 0.5173Msolution of acid?
strojnjashka [21]

<u>Answer:</u> The moles of hydrochloric acid is 1.0346\times 10^{-4}\mu mol

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Or,

\text{Molarity of the solution}=\frac{\text{Micro moles of solute}\times 10^6}{\text{Volume of solution (in }\mu L)}}

We are given:

Molarity of solution = 0.5173 M

Volume of solution = 200\mu L

Putting values in above equation, we get:

0.5173M=\frac{\text{Micro moles of HCl}\times 10^6}{200\mu L}\\\\\text{Micro moles of HCl}=1.0346\times 10^{-4}\mu mol

Hence, the moles of hydrochloric acid is 1.0346\times 10^{-4}\mu mol

7 0
3 years ago
Given the equation 2mg(s) + o2(g) → 2mgo(s) + 72.3 kj, how much heat is involved in the production of 5.0 mol of mgo? question 2
Rudik [331]
The heat is involved   in the  production of 5.0 mol of MgO  is   180 Kj

               calculation

2 Mg (s)   +O2 → 2 MgO

From  the  equation  above two  moles    of MgO  is used  therefore   

72.3   is for   2   moles

that is   72.3  kj =  2moles
                  ?      = 5  moles 

by  cross  multiplication

= 72.3  kj × 5/2     = 180  Kj  
    

7 0
3 years ago
When a solution of an acid reacts with a solution of a base, hydrogen ions react with hydroxide ions to form?
svetoff [14.1K]
Water
hydrogen ions+hydroxide=water
which can be verified by dark reaction of photosynthesis

3 0
3 years ago
Read 2 more answers
Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the sam
mafiozo [28]

Question:

Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the same as pure water at 20.0 degrees C (18 torr). The volume of the mixture is 1.7 L and its total pressure is 0.987 atm. Determine the number of moles of hydrogen gas present in the sample.

A. 0.272 mol

B. 0.04 mol

C. 0.997 mol

D. 0.139 mol

E. 0.0681 mol

Answer:

The correct option is;

E. 0.0681 mol

Explanation:

The equation for the reaction is

Zn + HCl = H₂ + ZnCl₂

Vapor pressure of the liquid = 18 torr = 2399.803 Pa

Total pressure of gas mixture H₂ + liquid vapor = 0.987 atm  

= 100007.775 Pa

Therefore, by Avogadro's law, pressure of the hydrogen gas is given by the following equation

Pressure of H₂ = 100007.775 Pa - 2399.803 Pa = 97607.972 Pa

Volume of H₂ = 1.7 L = 0.0017 m³

Temperature = 20 °C = 293.15 K

Therefore,

n = \frac{PV}{RT} =  \frac{100007.775 \times 0.0017 }{8.3145 \times 293.15} = 0.068078 \ moles

Therefore, the number of moles of hydrogen gas present in the sample is n ≈ 0.0681 moles.

7 0
3 years ago
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