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Harman [31]
3 years ago
15

What do changes in the biosphere, rising sea levels, drought and desertification, regional changes in temperature, and melting g

laciers have to do with one another
Physics
1 answer:
horrorfan [7]3 years ago
4 0
Alright I'm not an expert on this, so you'll probably have to verify it with someone more qualified, but here's my idea (the summary is underlined at the bottom, but I added an explanation just because):
Humans are increasing the CO2 levels in our atmosphere, trapping a lot of the sun's heat in. Increased heat increases the chance of desertification and drought, and also causes regional temperatures to go up. The sun's rays are also hitting the icecaps, but the ice itself reflects most of the sun. However, the ocean absorbs the heat, causing the water around the ice to become warmer, just enough to cause them to melt a bit. This melting makes the ocean level rise. <u>So to wrap up, humans are changing the biosphere causing the Earth to warm up, the icecaps and glaciers to melt, regional temperatures to increase, and the chance of desertification to also increase.</u>
It took me FOREVER to write and word this well so I hope this helps. =)
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Sheila eats an energy bar right before she goes on a run. What energy changes will occur in sheila as she runs after eating?
LiRa [457]
The energy bar eaten by Sheila has chemical energy locked up inside it. This chemical energy is converted to mechanical energy in form of potential and kinetic energy and this in turn is converted to heat energy as the run progresses. Thus, the energy changes are: chemical energy to mechanical energy [kinetic and potential] and finally to heat energy.
8 0
3 years ago
Read 2 more answers
A force of 55N accelerates a 7.5kg wagon at 5.3 m/s^2 along a road. How large is the frictional force?
Varvara68 [4.7K]

Answer:

<h2>15.25 N</h2>

Explanation:

       A force of 55\text{ }N is acting on a wagon along the road. The wagon weights 7.5\text{ }kg. Acceleration of the wagon is given as 5.3\text{ }\frac{m}{s^{2}}.

       Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.

       Gravitational Force and Normal Reaction cancel out each other.

       Net External Force = Mass of system/wagon \times Acceleration of wagon

       F_{ext}-F_{friction}=(7.5\text{ }kg)\times(5.3\text{ }\frac{m}{s^{2}})=39.75\text{ }N\\55\text{ }N-F_{friction}=39.75\text{ }N\\F_{friction}=15.25\text{ }N

F_{friction} has a negative sign because it opposes the motion of the wagon.

∴ Frictional Force = 15.25 N

4 0
3 years ago
Compare and contrast speed and velocity.​
vlabodo [156]

Speed is the time rate of an object moving from one place to another, while velocity is the rate and direction of the object's movement. They are very similar but they don't mean the same thing.

8 0
3 years ago
A solid conducting sphere of radius 2.00 cm has a charge of 6.88 μC. A conducting spherical shell of inner radius 4.00 cm and ou
zepelin [54]

Explanation:

Given that,

Radius R= 2.00

Charge = 6.88 μC

Inner radius = 4.00 cm

Outer radius  = 5.00 cm

Charge = -2.96 μC

We need to calculate the electric field

Using formula of electric field

E=\dfrac{kq}{r^2}

(a). For, r = 1.00 cm

Here, r<R

So, E = 0

The electric field does not exist inside the sphere.

(b). For, r = 3.00 cm

Here, r >R

The electric field is

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times6.88\times10^{-6}}{(3.00\times10^{-2})^2}

E=6.88\times10^{7}\ N/C

The electric field outside the solid conducting sphere and the direction is towards sphere.

(c). For, r = 4.50 cm

Here, r lies between R₁ and R₂.

So, E = 0

The electric field does not exist inside the conducting material

(d).  For, r = 7.00 cm

The electric field is

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times(-2.96\times10^{-6})}{(7.00\times10^{-2})^2}

E=5.43\times10^{6}\ N/C

The electric field outside the solid conducting sphere and direction is away of solid sphere.

Hence, This is the required solution.

6 0
3 years ago
Which of the following statements best describe the frequency of a wave?
Brrunno [24]

Answer:

I believe the answer is B.

6 0
3 years ago
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