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melamori03 [73]
2 years ago
12

Identify the precipitate that forms (if any) when aqueous solutions of barium nitrate and sodium sulfate are mixed.

Chemistry
1 answer:
Alborosie2 years ago
4 0

The precipitate that forms when aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate.

Barium Nitrate is a colorless to white, odorless, crystalline powder. It is used in making fireworks, for green lights and neon lights, and in ceramic glazes.

Sodium Sulfate Anhydrous is the anhydrous, sodium salt form of sulfuric acid. Sodium ion is the principal cation of the extracellular fluid and plays a large part in the therapy of fluid and electrolyte disturbances.

When aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate, one soluble salt, sodium nitrate, and an insoluble salt, barium sulphate.

Learn more about barium nitrate, click here brainly.com/question/9597126

#SPJ4

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What mass of hydrochloric acid (in grams) can 2.7 g of sodium bicarbonate neutralize? (Hint: Begin by writing a balanced equatio
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Answer:

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

Explanation:

Step 1: Data given

Mass of sodium bicarbonate = 2.7 grams

Step 2: The balanced equation

HCl + NaHCO3 ⇔  NaCl + H2O + CO2

Step 3: Calculate moles NaHCO3

moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles

Step 4: Calculate moles HCl

For 1 mol NaHCO3 we need 1 mol HCl

For 0.032 moles NaHCO3 = 0.032 moles HCl

Step 5: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

mass HCl = 0.032 * 36.46 g/mol= 1.17 grams

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

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A total of 2.00 mol of a compound is allowed to react with water in a foam coffee cup and the reaction produces 126 g of solutio
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Answer:

  • <u>0.976 kJ/mol</u>

Explanation:

A foam coffe cup is considered a perfectly insulated system: heat energy is not exchanged with the surroundings.

Under that assumption, the heat released by the chemical reaction is equal to the heat absorbed by the system.

1. Heat absorbed by the system:

Use the equation Heat = Q = m × C × ΔT, with:

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  • C = specific heat of pure water = 4.186 J/gºC
  • ΔT = increase of temperature = 24.70 ºC - 21.00ºC = 3.70ºC

Q = 126g × 4.186J/gºC × 3.70ºC = 1,951.5J

<em><u></u></em>

<em><u>2. Enthalpy of the reaction</u></em>

The enthalpy must be reported in kJ/mol.

Then, convert juoles to kilojoules, dividing by 1,000; and divide by 2.00 moles, which is the amount of compound that reacted:

  • ΔHrxn = 1,951.5J × (1kJ / 1,000J) × (1 / 2mol) ≈ 0.9758 kJ/mol

Round to <em>3 significant figures</em>: 0.976 kJ/mol

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