After eliminating common terms, the net reaction occurs when we combine the reactions of an acid protonating water and its conjugate base deprotonating water is<u> the autoionization of water.</u>
<h3>What is the autoionization of water?</h3>
The autoionization of water demonstrates that water can react with itself because acids and bases should interact with one another.
Here, the sound should be strange. Additionally, the water molecules should experience a small degree of proton exchange.
Thus, the correct option is c. The autoionization of water.
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The question is complete. Your complete question is given below:
a. The acid-base reaction between the acid and its conjugate base.
b. The synthesis of a complex between the acid and its conjugate base.
c. The autoionization of water.
d. None of the above.
How am I supposed to help you if there's not picture of what the problem is
Factors that increases reaction rate such as increase in concentration or pressure will reduce reaction time whereas factors that decrease reaction rate such as inhibitors will increase reaction time.
<h3>What are the factors that affect reaction rate?</h3>
Factors that affect reaction rate are those factors which increase or decrease the rate of chemical reaction.
The factors that affect reaction rate include:
- temperature
- concentration/pressure
- catalysts
- surface area
- nature of substance
Any factor that increases reaction rate such as increase in concentration or pressure will reduce reaction time whereas factors that decrease reaction rate such as inhibitors will increase reaction time.
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Answer:
Explanation:
Given parameters:
pH = 3.50
Unknown:
concentration of [H₃0⁺] = ?
concentration of [OH⁻] = ?
Solution:
In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.
pH = -log₁₀[H₃O⁺]
[H₃O⁺] = inverse log₁₀ (-pH) = 
= 
[H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³
For the [OH⁻]:
we use : pOH = -log₁₀ [OH⁻]
Recall: pOH + pH = 14
pOH = 14 - pH = 14 - 3.5 = 10.5
Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]
[OH⁻] = 
[OH⁻] = 
= 3.2 x 10⁻¹¹moldm⁻³
The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.
Answer:
5.3%
Explanation:
Let the volume be 1 L
volume , V = 1 L
use:
number of mol,
n = Molarity * Volume
= 0.8846*1
= 0.8846 mol
Molar mass of CH3COOH,
MM = 2*MM(C) + 4*MM(H) + 2*MM(O)
= 2*12.01 + 4*1.008 + 2*16.0
= 60.052 g/mol
use:
mass of CH3COOH,
m = number of mol * molar mass
= 0.8846 mol * 60.05 g/mol
= 53.12 g
volume of solution = 1 L = 1000 mL
density of solution = 1.00 g/mL
Use:
mass of solution = density * volume
= 1.00 g/mL * 1000 mL
= 1000 g
Now use:
mass % of acetic acid = mass of acetic acid * 100 / mass of solution
= 53.12 * 100 / 1000
= 5.312 %
≅ 5.3%
