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givi [52]
3 years ago
5

A sample of krypton gas with a volume of 10.00 L has a temp of 303 K and exerts

Chemistry
1 answer:
marshall27 [118]3 years ago
7 0

<u>Answer:</u> The final volume will be 14.85 L.

<u>Explanation:</u>

To calculate the final volume when temperature increases, we use Charles' Law.

This law states that volume is directly proportional to the temperature of the gas if number of moles and pressure remains constant.

V\propto T\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 = Initial volume and temperature

V_2\text{ and }T_2 = Final volume and temperature

We are given:

V_1=10L\\&#10;T_1=303K\\&#10;V_2=?L\\&#10;T_2=450K

Putting values in above equation, we get:

\frac{10L}{303K}=\frac{V_2}{450K}

V_2=14.85L

Hence, the final volume of the gas is 14.85L

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Calculate the molarity of the two solutions. The first solution contains 0.550 mol of NaOH in 1.40 L of solution.
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Answer:

0.393 mol/L.

Explanation:

The following data were obtained from the question:

Number of mole of NaOH = 0.550 mol

Volume of solution = 1.40 L

Molarity of NaOH =.?

Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the molarity of the NaOH solution as follow:

Number of mole of NaOH = 0.550 mol

Volume of solution = 1.40 L

Molarity of NaOH =.?

Molarity = mole / Volume

Molarity of NaOH = 0.55 / 1.4

Molarity of NaOH = 0.393 mol/L

Thus, the molarity of the NaOH solution is 0.393 mol/L.

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