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Len [333]
3 years ago
10

Use the solubility rules to determine if:

Chemistry
1 answer:
xenn [34]3 years ago
5 0

<u>Answer:</u>

A reaction is said to occur if there is a formation of an insoluble solid or a precipitate(s) or a liquid (l) or a gas(g).

If both the reactants and products are in aqueous state, No reaction takes place.

$2 \mathrm{NaCl}(a q)+M g B r_{2}(a q)>M g C l_{2}(a q)+2 \mathrm{NaBr}(a q)(\mathrm{NO} \text { REACTION })$

All chlorides and Bromides are soluble except that of Ag, Hg and Pb.

Hence, No reaction takes place since all the reactants and products are in aqueous states.

${KOH}(a q)+{NaCl}(a q)>K C l(a q)+{NaOH}(a q)(\mathrm{NO} \text { REACTION })$

Salts  of Group IA are soluble. Hence No reaction takes place

$M g S(a q)+2 {NaOH}(a q)>M g(O H)_{2}(s)+N a_{2} S(a q)$

(REACTION TAKES PLACE)

All hydroxides are insoluble except that of Group IA, ammonium ion and  Group IIA down from Calcium.

Hence Reaction takes place with the formation of Mg(OH)_2 precipitate

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Suppose that you are performing a titration on a monoprotic acid. Titration of this monoprotic acid required a volume of 0.1L of
Alex73 [517]

Answer: A) More base is likely required to reach the endpoint for the diprotic acid than for the monoprotic acid under these conditions

Explanation:

The monoprotic acid (HA) has a valency of 1 and diprotic acid  (H_2A) has a valency of 2.

As the concentration and volume of the diprotic acid and the monoprotic acids are equal.

The neutralization reaction for monoprotic acid is:

HA+BOH\rightarrow BA+H_2O

The neutralization reaction for diprotic acid is:

H_2A+2BOH\rightarrow B_2A+2H_2O

Thus more number of moles of base are required for neutralization of diprotic acid and thus the volume required will be more as concentration and volume of the diprotic acid and the monoprotic acids are equal.

6 0
3 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Svet_ta [14]

Answer:

V_1=23.3~mL

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

C_1*V_1=C_2*V_2

Now we can identify the variables:

C_1=~1.475_M

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If we plug all the values into the equation:

1.475_M*V_1=0.1374_M*250.0~mL

And we solve for V_1:

V_1=\frac{0.1374_M*250.0~mL}{1.475_M}

V_1=23.3~mL

I hope it helps!

8 0
3 years ago
Is ineffective collision's the answer? Please correct me if not, thank you. :)
AleksAgata [21]
Yes! You're correct! Hope this helps! :D
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Isotopes are different types of atoms of the same element, but with a different number of __________ ?
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Same things but with different numbers of neutrons in nuclei
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