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MaRussiya [10]
2 years ago
5

How much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is

3.85 × 105 km?
Physics
1 answer:
mafiozo [28]2 years ago
3 0

1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km

<h3>What is Speed ?</h3>

Speed is the distance travelled per time taken. It is a scalar quantity. And the S.I unit is meter per second. That is, m/s

In the given question, we want to find how much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 10^5 km.

What are the parameters to consider ?

The parameters are;

  • The distance S = 3.85 × 10^{5} km
  • The Speed of Light C = 3 × 10^{8} m/s
  • The time taken t = ?

Speed = distance S ÷ Time t

Convert kilometer to meter by multiplying it by 1000

C = S/t

3 × 10^{8} =  3.85 × 10^{8} / t

Make t the subject of formula

t = 3.85 × 10^{8} / 3 × 10^{8}

t = 1.2833

t = 1.3 s

Therefore, 1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km

Learn more about Speed here: brainly.com/question/4931057

#SPJ1

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What is the longest wavelength of radiation that possesses the necessary energy to break the bond 941?
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3 0
3 years ago
A particular engine has a power output of 8 kW and an efficiency of 37%. If the engine expels 10994 J of thermal energy in each
VARVARA [1.3K]

Answer:

(a) 17450.8 J (B) 1.239 sec

Explanation:

We have given power output =8 KW

Heat expelled = 10994 j

Efficiency =37% = 0.37

(A) We know that efficiency \eta =1-\frac{heat\ expelled}{heat\ input}

0.37=1-\frac{10994}{heat\ input}

Heat input =17450.8 J

(B) Work done by the engine is = 17450.8-10994=6456.8 j

Power output is given by 8 KW =8000 W

So time for each cycle is \frac{8000}{6456.8}=1.239 sec

3 0
3 years ago
If the absolute pressure of a gas is 550.280 kPa, its gage pressure is
aivan3 [116]

By definition we have to:

Pabs = Patm + Pg

Where,

Pabs: absolute pressure

Patm: atmospheric pressure

Pg: gage pressure

The atmospheric pressure is constant and its value is:

Patm = 101.325 kPa

Then, by clearing gage pressure we have:

Pg = Pabs - Patm

Substituting values we have:

Pg = 550.280 - 101.325\\Pg = 448.955 KPa

Answer:

If the absolute pressure of a gas is 550.280 kPa, its gage pressure is:

D. 448.955 kPa

4 0
3 years ago
Read 2 more answers
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