An electron moving perpendicular to a magnetic field of 3. 2 × 10-2 t moves in a circle of radius 0. 40 cm. how fast is this ele
1 answer:
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Answer:
Explanation:
The ball was moving with velocity of 20 m /s earlier in horizontal direction . Due to kicking, additional V velocity was added to it at 40° because he kicked it at this angle but the ball travelled in the direction of resultant which was making an angle of 30° with the horizontal .
From the relation of inclination of resultant
Tan θ = V sinα / (u + V cosα) where α is angle between u and V , θ is inclination of resultant
Tan30 =
20 + .766 V = 1.11 V
20 = .344 V
V = 58 m /s
To know the force , we shall apply concept of impulse
F x t = mv , F is force for time t creating a change of momentum mv
F x .1 = .4 x 58
F = 232 N
Answer:
The circuit is missing attached below is the required circuit
answer :
a) Ic = 1.944 mA
Rp = 288.66 kΩ
b) <em>The Emitter-base Junction of the BJT is forward biased while its collector-base junction is reverse biased</em>
Explanation:
Rc = 3.6 kΩ
VBE = 0.8 v
<u>1) predict Ic and specify Rp to establish Vce at 5 V </u>
we will apply Kirchhoff's voltage law to resolve this
solution attached below
b ) The BJT is said to be in Forward reverse bias because <em>The Emitter-base Junction of the BJT is forward biased while its collector-base junction is reverse biased</em>
