Answer:
The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Explanation:
Given that,
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.
The speed of sound in air is 343 m/s.
To find,
The wavelength range for the corresponding frequency.
Solution,
The speed of sound is given by the following relation as :
Wavelength for f = 45 Hz is,
Wavelength for f = 375 Hz is,
So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Answer:
y = 4 Sin (2πt)
Explanation:
Amplitude, A = 4
frequency, f = 1
Wave function is given by
y = A sinωt
where, ω is angular frequency
ω = 2 π f = 2 π x 1 = 2π
So, the desired wave function
y = 4 Sin (2πt)
Answer:
The heat capacity of a sample is 37.7 J/K.
Explanation:
Given that,
Submerged temperature of tissue sample = 275 K
Mass of liquid nitrogen= 2 kg
Temperature = 70 K
Final temperature = 75 K
We need to calculate the heat
Using formula of heat
Put the value into the formula
We need to calculate the heat capacity of a sample
Using formula of heat capacity
Put the value into the formula
Hence, The heat capacity of a sample is 37.7 J/K.
Answer:
1920watts
Explanation:
P=IV
P = 16 x 120 = 1920 watts
Volume will decrease if the heat remains constant