Answer:
I thinks is B
Explanation:
they just look harmful
I also researched and it says its harmful and causes sickness and death
From the gas law, PV=nRT we can say that P(pressure), V(volume) and T (temperature) are related to each other. The initial volume of sample is 408 ml
Given that initial volume of the sample = V1
initial pressure of the sample = 0.92atm
initial temperature of the sample = 23.2oC
Final pressure of the sample = 1.3atm
Final temperature of the sample = 40.1 oC
Final volume of the sample = 500ml = 0.5L
Using the relation P1V1/T1 = P2V2/T2
V1 = 1.3x0.5x23.2/40.1x0.92 = 15.08/36.892 = 0.408
Hence the initial volume of sample = 408 ml
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Initial pressure of the gas = 65.3 kPa
Initial volume of the gas = 654 cm³
Initial temperature of the gas = 6⁰C = 273 + 6 = 279 K
Final pressure of the gas = 108.7 kPa
Final temperature of the gas = 4⁰C = 273 + 4 = 277 K
Using the combined gas law for ideal gases:
P₁V₁/T₁ = P₂V₂/T₂
where P₁, V₁ and T₁ are the pressure, volume and temperature for the initial state and P₂, V₂ and T₂ are the pressure, volume and temperature for the final state.
Plugging the given data into the combined gas law we have,
(65.3 kPa x 654 cm³) / (279 K) = (108.7 kPa x V₂)/(277 K)
V₂ = (65.3 kPa x 654 cm³ x 277 K) / (279 K x 108.7 kPa)
V₂ = 390.1 cm³
In general, we have this rate law express.:
![\mathrm{Rate} = k \cdot [A]^x [B]^y](https://tex.z-dn.net/?f=%5Cmathrm%7BRate%7D%20%3D%20k%20%5Ccdot%20%5BA%5D%5Ex%20%5BB%5D%5Ey)
we need to find x and y
ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).
then we go to compare two experiments in which only one concentration is changed
compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]
Δ[B]= 0.3 / 0.1 = 3
now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:
ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...
solve for y in the equation
![\Delta \mathrm{Rate} = \Delta [B]^y](https://tex.z-dn.net/?f=%5CDelta%20%5Cmathrm%7BRate%7D%20%3D%20%5CDelta%20%5BB%5D%5Ey)

To this point,
![\mathrm{Rate} = k \cdot [A]^x [B]^1](https://tex.z-dn.net/?f=%5Cmathrm%7BRate%7D%20%3D%20k%20%5Ccdot%20%5BA%5D%5Ex%20%5BB%5D%5E1%20)
do the same to find x.
choose two experiments in which only the concentration of B is unchanged:
Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4
solve for x for
![\Delta \mathrm{Rate} = \Delta [A]^x](https://tex.z-dn.net/?f=%5CDelta%20%5Cmathrm%7BRate%7D%20%3D%20%5CDelta%20%5BA%5D%5Ex)

the rate law is
Rate = k·[A]²[B]