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marusya05 [52]
4 years ago
15

PLS HELP IF YOU WANT A BRAINLIEST BEST ANSWER CHOICE, GETS A BRAINLIEST

Chemistry
2 answers:
nataly862011 [7]4 years ago
8 0

Answer:

25%

Explanation:

1/4 of the seeds are green, and 1/4 is 25%. So, the green seed is 25%.

Natalija [7]4 years ago
4 0

Answer:

It would be 25% because each equals 25%.

Explanation:

There is 4 "shapes" each can equal 25 because 25+25+25+25=100.

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Which of the following is true about nuclear power?
puteri [66]

Answer:

I thinks is B

Explanation:

they just look harmful

I also researched and it says  its harmful and causes sickness and death

5 0
2 years ago
a sample of gas initially at 0.92 atm and a temperature of 23.2 oc is heated to 40.1 oc. the resulting pressure is 1.3 atm which
Sliva [168]

From the gas law, PV=nRT we can say that P(pressure), V(volume) and T (temperature) are related to each other. The initial volume of sample is 408 ml

Given that initial volume of the sample = V1

initial pressure of the sample = 0.92atm

initial temperature of the sample = 23.2oC

Final pressure of the sample = 1.3atm

Final  temperature of the sample = 40.1 oC

Final  volume of the sample = 500ml = 0.5L

Using the relation P1V1/T1 = P2V2/T2

V1 = 1.3x0.5x23.2/40.1x0.92 = 15.08/36.892 = 0.408

Hence the initial volume of sample = 408 ml

To learn more about pressure click here brainly.com/question/12971272

#SPJ4

6 0
2 years ago
For the following gases, correct the volumes to the conditions indicated. A.654 cm3 at 6 degrees Celsius and 65.3 kPa to 4 degre
leva [86]

Initial pressure of the gas = 65.3 kPa  

Initial volume of the gas = 654 cm³

Initial temperature of the gas = 6⁰C = 273 + 6 = 279 K

Final pressure of the gas = 108.7 kPa

Final temperature of the gas = 4⁰C = 273 + 4 = 277 K

Using the combined gas law for ideal gases:

P₁V₁/T₁ = P₂V₂/T₂  

where P₁, V₁ and T₁ are the pressure, volume and temperature for the initial state and P₂, V₂ and T₂ are the pressure, volume and temperature for the final state.

Plugging the given data into the combined gas law we have,

(65.3 kPa x 654 cm³) / (279 K) = (108.7 kPa x V₂)/(277 K)

V₂ = (65.3 kPa x 654 cm³ x 277 K) / (279 K x 108.7 kPa)

V₂ = 390.1 cm³


8 0
3 years ago
The hybridization associated with the central atom of a molecule in which all the bond angles are 180° is ____.
enot [183]

Answer:

Sp hybrid

Explanation:

Sp is linear I n shape

7 0
4 years ago
RATE LAW QUESTION !
vivado [14]
In general, we have this rate law express.:

\mathrm{Rate} = k \cdot [A]^x [B]^y
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4)  by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation \Delta \mathrm{Rate} = \Delta [B]^y

3.09 = (3)^y \implies y \approx 1

To this point, \mathrm{Rate} = k \cdot [A]^x [B]^1

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for \Delta \mathrm{Rate} = \Delta [A]^x

4=  (2)^x \implies x = 2

the rate law is

Rate = k·[A]²[B]
6 0
3 years ago
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