Question

a 15.0 kg block is dragged over a rough, horizontal surface by a 70n force acting at 20degrees above the horizontal. the block is displaced 5.oo m, and the coefficient of kinetic friction is 0.300. find the work done on the block by The 70N force ,The normal force. The gravitational force.

Answer 1

Answer:

See below

Explanation:

See diagram below

  Horizontal force of the 70 N :      70 cos 20

  Vertical force of    the 70 N  :    

                                            70 sin20 <====this lessens the normal force, Fn

Gravitational force = mg = 15 (9.81) = 147.15 N

Work = force * distance =    (70 cos 20 N - Ff   )   * 5 M =  144.1  J