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vovangra [49]
2 years ago
9

a 15.0 kg block is dragged over a rough, horizontal surface by a 70n force acting at 20degrees above the horizontal. the block i

s displaced 5.oo m, and the coefficient of kinetic friction is 0.300. find the work done on the block by The 70N force ,The normal force. The gravitational force.
Physics
1 answer:
jenyasd209 [6]2 years ago
4 0

Answer:

See below

Explanation:

See diagram below

  Horizontal force of the 70 N :      70 cos 20

  Vertical force of    the 70 N  :    

                                            70 sin20 <====this lessens the normal force, Fn

Gravitational force = mg = 15 (9.81) = 147.15 N

Work = force * distance =    (70 cos 20 N - Ff   )   * 5 M =  144.1  J

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Answer:

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Explanation:

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R.d = λ₁/λ₂.................. Equation 1

making λ₂ the subject of equation 1

λ₂ = λ₁/R.d...................... Equation 2

R.d = refractive index of water , λ₁ = wave length of light in air, λ₂ = wave length of light in water

<em>Given: R.d = 1.33, λ₁ = 760nm</em>

<em>Substituting these values into equation 2</em>

λ₂  = 760/1.33

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3 years ago
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Explanation:

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V_{x}= A cos \alpha -B cos \beta=0  (1)\\V_{y}= A sin \alpha +B sin \beta - C=0   (2)

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