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sammy [17]
2 years ago
7

What is the mass of a 5.00cm3 piece of copper having a density of 8.96g/cm3

Chemistry
1 answer:
r-ruslan [8.4K]2 years ago
4 0

Answer:

44.8 grams

Explanation:

The density exists as a ratio comparing the mass of a piece of copper per 1 cm³. Since you have been given a new volume, you can set up a proportion to find the new mass.

\frac{8.96 grams}{1.00 cm^3} =\frac{?grams}{5.00cm^3}                                         <----- Proportion

44.8 = (1.00cm^3)(?grams)                              <----- Cross-multiply

44.8= ?grams                                                 <----- Divide both sides by 1.00

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frosja888 [35]

Answer:

2,7 m

Explanation:

You can solve this doing an energy balance:

m*g*h-\frac{1}{2} *m*v^{2} =41,7[J]

Solving this equation to get h:

\frac{41,7- \frac{1}{2} *m*v^{2} }{m*g}=h

Replacing the values and solving brings to 2,7 m

6 0
3 years ago
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How is this SI unit of temperature related to the metric unit of Celsius?
shtirl [24]

Answer:

Celsius is currently a derived unit for temperature in the SI system, kelvin being the base unit. ... The two main reference points of the Celsius scale were the freezing point of water (or melting point of ice) being defined as 0 °C and the boiling point of water being 100 °C.

Explanation:

Hope it helps

3 0
3 years ago
How many molecules are in 85g of silver nitrate?
maksim [4K]
<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Writing Compounds
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

85 g AgNO₃ (silver nitrate)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})
  2. Multiply/Divide:                                                                                                \displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

6 0
3 years ago
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Answer: Option (a) is the correct answer.

Explanation:

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where,     n = principle quantum number  

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Values of n can be 1, 2, 3, 4 and so on. Whereas the values of l can be 0, 1, 2, 3, and so on.

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So, when n = 1 then l = 0 and m = 0.

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And, n = 1 is the lowest energy level. Therefore, we can conclude that the ground state of an atom means all of the quantum numbers have their lowest values (n = 1,ℓ = mℓ = 0).

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Answer:

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