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1 year ago

Why does the ball orbit the Earth when launched from the theoretical cannon of Newton?

1 answer:

4 0

The ball orbit the Earth, when launched from the theoretical cannon of Newton, is option B. it is magnetically attracted.

<h3>Newton's Cannonball:</h3>

Newton's cannonball was a hypothetical situation. Isaac Newton once proposed that gravity, which he believed to be a universal force, was the primary factor behind the planetary motion. In this experiment, Newton imagines projecting a stone or a cannonball onto the summit of a very tall mountain. The body should move away from Earth in the direction it was projected if there were no effects from gravity or air resistance.

Depending on the projectile's initial velocity and the gravitational force acting on it, the bullet will travel in a different direction. Low speeds result in a simple fallback to Earth. The Earth's surface causes the cannonball to deviate from its elliptical route.

Learn more about Newton's Cannonball here:

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3 years ago

Read 2 more answers

Explain why xrays are used to take images of inside the body but UV isnt

Sidana [21]

Answer:

X-rays go all the way through the body, but ultraviolet rays do not.

Explanation:

An x-ray will show inside the body, but uv light isn't strong enough to go all the way through the body.

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2 years ago

A block is attached to a horizontal spring. On top of this block rests another block. The two-block system slides back and forth

Minchanka [31]

Answer:

Angular frequency will increase

No change in the amplitude

Explanation:

At extreme end of the SHM the energy of the SHM is given by

$E = \frac{1}{2} (m_1 + m_2)\omega^2 A^2$

here we know that

$\omega^2 = \frac{k}{m_1 + m_2}$

now at the extreme end when one of the mass is removed from it

then in that case the angular frequency will change

$\omega'^2 = \frac{k}{m_1}$

So angular frequency will increase

but the position of extreme end will not change as it is given here that the top block is removed without disturbing the lower block

so here no change in the amplitude

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3 years ago

What object oriented feature can we use to have a single test program, with one set of method calls in which the user can decide

SVETLANKA909090 [29]

Answer:

The answer is "Polymorphism".

Explanation:

Polymorphism is a feature of the object-oriented programming (OOPs) language, in which data or an object is dividing into more than one form. In other words, we can say that the capacity of various objects to obtain and react in different ways is polymorphism. It enables interaction with both objects and common interfaces that hide various details of their implementation.

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3 years ago

2. How far will a bird have traveled in 13 seconds if it maintained a speed of 31 m/s?

Flura [38]

speed of bird = 31 m/s

time = 13 s

since here bird maintains its speed to be constant

so here the distance traveled is given by

$d = v*t$

$d = 31 * 13$

$d = 403 m$

so bird will travel 403 m distance while maintaining its speed to be constant

average speed is the ratio of total distance covered and total time

here Ian walk 2 km then 0.5 km and then 2.5 km so the total distance is given as

$d = d_1 + d_2 + d_3$

$d = 2 + 0.5 + 2.5$

$d = 5 km$

total time of his full motion is

$t = 3 hours$

so the average speed of the motion is

$v = \frac{d}{t}$

$v = \frac{5}{3} = 1.67 km/h$

so here average speed of Ian is 1.67 km/h

Initial speed of the truck is 6 m/s

after 4 s interval of time

final speed of the truck is 14 m/s

so the acceleration is rate of change in velocity

so it is given as

$a = \frac{v_f - v_i}{t}$

$a = \frac{14 - 6}{4}$

$a = 2 m/s^2$

so here truck accelerated with 2 m/s^2

Here car starts from rest so its initial speed is 0

after 2.5 s interval of time

final speed of the car is 15 m/s

so the acceleration is rate of change in velocity

so it is given as

$a = \frac{v_f - v_i}{t}$

$a = \frac{15 - 0}{2.5}$

$a = 6 m/s^2$

so here car accelerated with 6 m/s^2

a bag full of trash is dropped from the balcony

Here we can say when bag is in air

the net force on the bag is only due to its weight

so here we can use Newton's II law to find the acceleration of bag

$F = ma$

$mg = ma$

$a = g = 9.8 m/s^2$

so here bag will have constant acceleration during its whole motion as we can see that there is no change in the force and hence its acceleration always remains constant

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3 years ago