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1 year ago

Why does the ball orbit the Earth when launched from the theoretical cannon of Newton?

1 answer:

4 0

The ball orbit the Earth, when launched from the theoretical cannon of Newton, is option B. it is magnetically attracted.

<h3>Newton's Cannonball:</h3>

Newton's cannonball was a hypothetical situation. Isaac Newton once proposed that gravity, which he believed to be a universal force, was the primary factor behind the planetary motion. In this experiment, Newton imagines projecting a stone or a cannonball onto the summit of a very tall mountain. The body should move away from Earth in the direction it was projected if there were no effects from gravity or air resistance.

Depending on the projectile's initial velocity and the gravitational force acting on it, the bullet will travel in a different direction. Low speeds result in a simple fallback to Earth. The Earth's surface causes the cannonball to deviate from its elliptical route.

Learn more about Newton's Cannonball here:

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Using a schematic diagram, explain the steps of the laser technique.

nignag [31]

The steps of the use of the laser technique is explained below:

A laser beam is emitted from the diode in the unit and spread into a laser plane (1).
The laser plane, appearing as a line on the sphere (2), is reflected and collected by dual CCD arrays (1).
The resulting 2D profile is digitized and as the unit travels along the x-axis of the object, multiple profiles are collected yielding a 3D coordinate point cloud of the surface (3).

<h3>What is a Laser Technique?</h3>

This refers to the type of surgery that makes use of special light beams in order to cut open the human body in a surgical procedure.

Hence, we can see that the laser technique is considered safer than conventional surgical methods.

Laser techniques include:

laser vaporization,
laser resection-enucleation,
coagulation.

Read more about laser technique here:

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3 0

2 years ago

K-2/5=11k literal equations

krek1111 [17]

-2/5 = 11k - k
-2/5 = 10k
-2/5/10 = k
-2/5 * 10 = k
-2/50 = k
k = -1/25.

-1/25 - 2/5 = 11k is true.

6 0

3 years ago

An object pulled to the right by two forces has an acceleration of 2.5m/s2. The free-body diagram shows the forces acting on the

Vanyuwa [196]

Answer:

490 N is the correct answer.

Explanation:

8 0

3 years ago

Anybody got any answers???

dexar [7]

Answer:

b? to a?

Explanation:

6 0

3 years ago

Read 2 more answers

The cabinet is mounted on coasters and has a mass of 45 kg. The casters are locked to prevent the tires from rotating. The coeff

stira [4]

Answer:

the force P required for impending motion is 132.3 N

the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

Explanation:

Given that:

mass of the cabinet m = 45 kg

coefficient of static friction μ = 0.30

A free flow body diagram illustrating what the question represents is attached in the file below;

The given condition from the question let us realize that ; the casters are locked to prevent the tires from rotating.

Thus; considering the forces along the vertical axis ; we have :

$\sum f_y =0$

The upward force and the downward force is :

$N_A+N_B = mg$

where;

$\mathbf { N_A \ and \ N_B}$ are the normal contact force at center point A and B respectively .

$N_A+N_B = 45*9.8$

$N_A+N_B = 441$ ------- equation (1)

Considering the forces on the horizontal axis:

$\sum f_x = 0$

$F_A +F_B = P$

where ;

$\mathbf{ F_A \ and \ F_B }$ are the static friction at center point A and B respectively.

which can be written also as:

$\mu_s N_A + \mu_s N_B = P$

$\mu_s( N_A + N_B) = P$

replacing our value from equation (1)

P = 0.30 ( 441)

P = 132.3 N

Thus; the force P required for impending motion is 132.3 N

b) Since the horizontal distance between the casters A and B is 480 mm; Then half the distance = 480 mm/2 = 240 mm = 0.24 cm

the largest value of "h" allowed for the cabinet is not to tip over is calculated by determining the limiting condition of the unbalanced torque whose effect is canceled by the normal reaction at $N_A$ and it is shifted to $N_B$ :

Then:

$\sum M _B = 0$

$P*h = mg*0.24$

$h =\frac{45*9.8*0.24}{132.3}$

h = 0.8 m

Thus; the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

6 0

3 years ago