The meter is connected to perform a diagnostic check. Which type of fault can be isolated using the meter when connected as show
1 answer:
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Answer:
The tube surface temperature immediately after installation is 120.4°C and after prolonged service is 110.8°C
Explanation:
The properties of water at 100°C and 1 atm are:
pL = 957.9 kg/m³
pV = 0.596 kg/m³
ΔHL = 2257 kJ/kg
CpL = 4.217 kJ/kg K
uL = 279x10⁻⁶Ns/m²
KL = 0.68 W/m K
σ = 58.9x10³N/m
When the water boils on the surface its heat flux is:
For copper-water, the properties are:
Cfg = 0.0128
The heat flux is:
qn = 0.9 * 18703.42 = 16833.078 W/m²
The tube surface temperature immediately after installation is:
Tinst = 100 + 20.4 = 120.4°C
For rough surfaces, Cfg = 0.0068. Using the same equation:
ΔT = 10.8°C
The tube surface temperature after prolonged service is:
Tprolo = 100 + 10.8 = 110.8°C
Answer:
Explanation:
From the given question:
Using the distortion energy theory to determine the factors of safety FOS can be expressed by the relation:
where; syt = strength in tension and compression = 350 MPa
The maximum shear stress theory can be expressed as:
where;
a. Using distortion - energy theory formula:
FOS = 2.183
USing the maximum-shear stress theory;
FOS = 1.977
b. σx = 110 MPa, σy = 100 MPa
Using distortion - energy theory formula:
FOS =3.322
USing the maximum-shear stress theory;
FOS = 350/2×25
FOS = 350/50
FOS = 70
c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa
Using distortion- energy theory formula:
FOS = 350/88.88
FOS = 3.939
USing the maximum-shear stress theory;
FOS = 4.341
Answer:
number of pulses produced = 162 pulses
Explanation:
give data
radius = 50 mm
encoder produces = 256 pulses per revolution
linear displacement = 200 mm
solution
first we consider here roll shaft encoder on the flat surface without any slipping
we get here now circumference that is
circumference = 2 π r .........1
circumference = 2 × π × 50
circumference = 314.16 mm
so now we get number of pulses produced
number of pulses produced = × No of pulses per revolution .................2
number of pulses produced = × 256
number of pulses produced = 162 pulses
Answer:
=
in thirty seconds.
Explanation:
one thirty second is one part out of 32 equal section . It is used to describe amounts accurately.
can be easily expressed as