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3 years ago

SB-4 Which one of the following is true about red buoys under the U.S. Aids to Navigation System?

Engineering

1 answer:

stich3 [128]3 years ago

8 0

Question:

1. Some are known as "nun" buoys

2. They are labeled with odd numbers

3. If it is lighted, the light color is green

4. Some are known as "can" buoys

Answer:

The correct option is;

1. Some are known as "nun" buoys

Explanation:

Based on the lateral system, on the starboard side, one can find the red even numbered marks while the odd-numbered, green, marks are located on the port side of a channel such that the buoy numbers increase as a vessel travels upstream.

The red buoys are cones shaped in appearance and have triangular reflective sign markings embossed and they are of different types included in the order of lower water depth

1. NUN buoy

2. Lighted buoy

3. Light

4. Day beacon

Therefore, the correct option is 1. Some are known as "NUN" buoys.

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You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea

Reika [66]

Answer: 33.35 minutes

Explanation:

A(t) = A(o) *(.5)^[t/(t1/2)]....equ1

Where

A(t) = geiger count after time t = 100

A(o) = initial geiger count = 400

(t1/2) = the half life of decay

t = time between geiger count = 66.7 minutes

Sub into equ 1

100=400(.5)^[66.7/(t1/2)

Equ becomes

.25= (.5)^[66.7/(t1/2)]

Take log of both sides

Log 0.25 = [66.7/(t1/2)] * log 0.5

66.7/(t1/2) = 2

(t1/2) = (66.7/2 ) = 33.35 minutes

4 0

3 years ago

Hello, I have a question, I would be glad if you can help.

Anastasy [175]

Answer:

infinite

Explanation:

The tangent of the angle the arm makes with the vertical will be the ratio of the centripetal acceleration to the acceleration due to gravity on the center of mass of the arm. The angle can only be 90° (fully-open arms) if that ratio is infinite.

The speed must be infinite for the arms to be fully open.

3 0

2 years ago

An inductor (L = 400 mH), a capacitor (C = 4.43 µF), and a resistor (R = 500 Ω) are connected in series. A 44.0-Hz AC generator

MakcuM [25]

Answer:

(A) Maximum voltage will be equal to 333.194 volt

(B) Current will be leading by an angle 54.70

Explanation:

We have given maximum current in the circuit $i_m=385mA=385\times 10^{-3}A=0.385A$

Inductance of the inductor $L=400mH=400\times 10^{-3}h=0.4H$

Capacitance $C=4.43\mu F=4.43\times 10^{-3}F$

Frequency is given f = 44 Hz

Resistance R = 500 ohm

Inductive reactance will be $x_l=\omega L=2\times 3.14\times 44\times 0.4=110.528ohm$

Capacitive reactance will be equal to $X_C=\frac{1}{\omega C}=\frac{1}{2\times 3.14\times 44\times 4.43\times 10^{-6}}=816.82ohm$

Impedance of the circuit will be $Z=\sqrt{R^2+(X_C-X_L)^2}=\sqrt{500^2+(816.92-110.52)^2}=865.44ohm$

So maximum voltage will be $\Delta V_{max}=0.385\times 865.44=333.194volt$

(B) Phase difference will be given as $\Phi =tan^{-1}\frac{X_C-X_L}{R}=\frac{816.92-110.52}{500}=54.70$

So current will be leading by an angle 54.70

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3 years ago

If they opened up the International Space Station to tourism, would you go? Why? answer in 2 sentences

Arlecino [84]

Personally, I would go to the space station. The space station has extreme different levels of technology and abilities, plus who doesn’t want to go to space.

6 0

3 years ago

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I need a thesis statement about Engineers as Leaders.

algol [13]

Answer:

Engineers are a very beneficial contribution in which offers great solutions to national problems.

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3 years ago