Answer:
Gage pressure at the bottom of the tank = 46.1kP
Explanation:
Note that it is required to expressed the gage pressure ,pressure at the free surface=0 gage
Pressure due to the oil layer= (3m)*((800kg/m^3)(9.81m/s^2))/1000=25.9kpa
Pressure due to the brine layer=(2m)*((1030kg/m^3)(9.81m/s^2))/1000=20.2ka
Therefore, the pressure at the bottom=25.9+20.2=46.1kP
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Answer:
22.90 × 10⁸ kg
Explanation:
Given:
Diameter, d = 0.02 m
ωₙ = 0.95 rad/sec
Time period, T = 0.35 sec
Now, we know
T=
where, L is the length of the steel cable
g is the acceleration due to gravity
0.35=
or
L = 0.0304 m
Now,
The stiffness, K is given as:
K =
Where, A is the area
E is the elastic modulus of the steel = 2 × 10¹¹ N/m²
or
K =
or
K = 20.66 × 10⁸ N
Also,
Natural frequency, ωₙ =
or
mass, m =
or
mass, m =
mass, m = 22.90 × 10⁸ kg
Explanation:
1140 miliohms.
resistance = resistivity×length /area
= 0.0000000171 ohms x 100 meters / 1.5 mm^2