Answer:
0.5 Ohms
Explanation:
We note that the node Q is also between the resistors of 1ohm and 2ohms.
We note that the node P is also between the resistors of 2ohms and 3ohms.
Thus, all these resistors are in parallel, beween nodes P and Q
1/Re=1/R1+1/R2+1/R3
1/Re=1/1+1/2+1/3=(6+3+2)/6=11/6 [ohm^(-1)]
Re=6/11=0.54ohms
Rounding to the tenth: Re=0.5 ohms
Well what are you comparing or try to pair together?
Answer:α = 1.00 rad/s², τ = 90.0 N•m, KEr = 1.12 kJ
Explanation:
m = 795/9.81 = 81.0 kg
ω₁ = 47.79 rev/min(2π rad/rev) / (60 s/min) = 5.00 rad/s
α = (ω₁ - ω₀)/τ = (5.00 - 0.00)/5.00 = 1.00 rad/s²
I = ½mR² = ½(81.0)(1.49²) = 90.0 kg•m²
τ = Iα = 90.0(1.00) = 90.0 N•m
KEr = ½Iω² = ½(90.0)5.00² = 1,124.477 ≈ 1.12 kJ
Angles will probably be 96° 35° and 49°
I tried to explain it with the working out, just re arrange the cosine rule for angles instead of side lengths.
if you need it explaining at all just message me :)
hoped it helped
Just about ALL science and math problems are solved by using
GIVEN information to work out the unknown information.
No information given ===> no answer.