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Rashid [163]
3 years ago
12

water has an index of refraction of 1.33. What is the critical angle for light leaving a pool of water into air? 0 37 90 49

Physics
1 answer:
vesna_86 [32]3 years ago
6 0
When light travels from a medium with higher refractive index into a medium with lower refractive index, there is a maximum angle (called critical angle) for which all the light is reflected, so there is no refraction.

The value of the critical angle is given by:
\theta = \arcsin ( \frac{n_2}{n_1} )
when n1 is the refractive index of the first medium, while n2 is the refractive index of the second medium. In our case, n1=1.33 (the water) and n1=1.00 (the air). Putting numbers in, we get
\theta = \arcsin ( \frac{1.00}{1.33} )=49^{\circ}
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