In an rlc ac circuit, the values of the inductance and capacitance are both doubled. as a result of this change, the resonance f
1 answer:
f = 1 / 4 * Π *
The resonant frequency becomes half.
In resonance, =
-------- (1)
Where, ,
are the inductive and capacitive reactance of the RLC AC circuit.
We know that,
= 2 * Π * f * L
= 1 / 2 * Π * f * C
Where f is the frequency.
substituting the values of inductive and capacitive reactance in equation (1).
2 * Π * f * L = 1 / 2 * Π * f * C
On solving we get
= 1 / 4 * Π * Π * L * C
Therefore, f = 1 / 2 * Π *
As values of L and C are doubled.
L = 2 * L
C = 2 * C
f = 1 / 2 * Π *
f = 1 / 4 * Π *
Hence, the resonant frequency becomes half.
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