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svp [43]
1 year ago
12

In an rlc ac circuit, the values of the inductance and capacitance are both doubled. as a result of this change, the resonance f

requency of the circuit is?
Physics
1 answer:
Pavlova-9 [17]1 year ago
7 0

f = 1 / 4 *  Π *    \sqrt{L * C}

The resonant frequency becomes half.

In resonance, X_{L}= X_{C} -------- (1)

Where, X_{L},  X_{C} are the inductive and capacitive reactance of the RLC AC circuit.

We know that,

X_{L} =  2 * Π * f  * L

X_{C} = 1 / 2 * Π * f * C

Where f is the frequency.

substituting the values of inductive and capacitive reactance in equation (1).

2 * Π * f  * L =  1 / 2 * Π * f * C

On solving we get

f^{2} = 1 / 4 * Π *  Π *  L * C

Therefore, f = 1 / 2 *  Π * \sqrt{L * C}

As values of L and C are doubled.

L = 2 * L

C = 2 * C

f = 1 / 2 * Π *  \sqrt{4 * L * C}

f = 1 / 4 *  Π *    \sqrt{L * C}

Hence, the resonant frequency becomes half.

Find more information using the link below:

brainly.com/question/15595203

# SPJ4

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From the question,

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