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dlinn [17]
2 years ago
8

What constant acceleration is required to increase the speed of a car from 27 mi/h to 53 mi/h in 3s?

Physics
1 answer:
mario62 [17]2 years ago
7 0

Answer:

8.87 m/s^2  

Explanation:

Acceleration is change in velocity over a change in time

27 to 53 = 26 m/s   change in velocity

26 m/s / 3 s = 8.87 m /s^2

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“You can’t get more energy from a machine than the amount of energy you put into it,” is one way of stating the law of conservat
goldenfox [79]

Answer:

Energy

Explanation:

One ways of stating the law of conservation of energy is that "you cannot get more energy from a machine than the amount of energy you put into it".

The law of conservation of energy states that in a system, energy is neither created nor destroyed but transformed from one form to another.

The energy in a system does not increase based on the premise of this law.

  • The efficiency of a machine can reduce but the energy is always conserved.
  • This is because energy is transformed to other forms.
5 0
3 years ago
A small ball (mass of 0.5 kg) and a large brick (mass of 10 kg) are dropped from a height of 5 meters. Both items are released a
Anna71 [15]

Explanation:

neglecting air resistance both will land at the same moment.

both have therefore the same acceleration.

7 0
3 years ago
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Red light of wavelength 651 nm produces photoelectrons from a certain photoemissive material. Green light of wavelength 521 nm p
Mnenie [13.5K]

Answer:

material work function is 0.956 eV

Explanation:

given data

red wavelength 651 nm

green wavelength 521 nm

photo electrons = 1.50 × maximum kinetic energy

to find out

material work function

solution

we know by Einstein photo electric equation  that is

for red light

h ( c / λr ) = Ф +  kinetic energy

for green light

h ( c / λg ) = Ф +  1.50 × kinetic energy

now from both equation put kinetic energy from red to green

h ( c / λg ) = Ф +  1.50 × (h ( c / λr ) - Ф)

Ф =( hc / 0.50) × ( 1.50/ λr  - 1/ λg)

put all value

Ф =( 6.63 ×10^{-34} (3 ×10^{8} )  / 0.50) × ( 1.50/ λr  - 1/ λg)

Ф =( 6.63 ×10^{-34} (3 ×10^{8} ) / 0.50 ) × ( 1.50/ 651×10^{-9}   - 1/ 521 ×10^{-9})

Ф = 1.5305  ×10^{-19} J  × ( 1ev / 1.6 ×10^{-19} J )

Ф = 0.956 eV

material work function is 0.956 eV

4 0
3 years ago
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A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is supported by an upward force o
Rainbow [258]

Answer:

5..No work is being done.

Explanation:

Hello!

Remember that the concept of work is defined as the force required to move a certain body distance, it is calculated as the product of force by distance.

therefore, the work required to raise the box is 150J.

However, the work required to keep the box lifted without moving is zero since although the box has a force due to the weight it does not move.

6 0
3 years ago
Need help ASAP please helppp
Setler [38]

Answer:

2.3 newtons of force

Explanation:

Divide the weight by the speed of the bike

4 0
3 years ago
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