Convert 16.1 km/h to meters per second

Our Sun emits most of its radiation at a wavelength of 550 nm. If a star were 3.50 times hotter than our Sun, it would emit most

Wittaler [7]

The wavelength of the radiation emitted by the star is 183 nm.

Explanation:

As per Wien's displacement law, the product of emitted wavelength and temperature of the star will be equal to 2.898 × 10⁻³ mK.

$T*wavelength = 2.898 * 10^{-3}$

So if the wavelength of the emitted radiation by Sun is given as 550 nm, then the temperature of the Sun will be

$Temperature of Sun = \frac{2.898*10^{-3} }{wavelength}$

$Temperature of Sun = \frac{2.898*10^{-3} }{550 * 10^{-9} } = 5.27 * 10^{3} K$

Then if the temperature of star is said to be 3.5 times hotter than Sun, then the temperature of Star = 3.5×5.27×10³ = 15.81×10³ K.

With this temperature, the wavelength of the emitted radiation can be found as follows:

$Wavelength = \frac{2.898 * 10^{-3} }{15.81 * 10^{3} } =183 nm$

So, the wavelength of the radiation emitted by the star is 183 nm.

8 0

3 years ago

g A small car travels up the hill with a speed of v = 0.2 s (m/s) where s is the distance measured from point A in meters. Deter

jasenka [17]

Answer:

The magnitude of the acceleration of the car when $s = 50\,m$ is $2\,\frac{m}{s^{2}}$ .

Explanation:

The acceleration can be obtained by using the following differential equation:

$a = v \cdot \frac{dv}{ds}$

Where $a$ , $v$ and $s$ are the acceleration, speed and distance masured in meters per square second, meters per second and meters, respectively.

Given that $v = 0.2\cdot s$ , its first derivative is:

$\frac{dv}{ds} = 0.2$

The following expression is obtained by replacing each term:

$a = 0.2\cdot 0.2\cdot s$

$a = 0.04\cdot s$

The magnitude of the acceleration of the car when $s = 50\,m$ is:

$a = 0.04\cdot (50\,m)$

$a = 2\,\frac{m}{s^{2}}$

5 0

3 years ago

A 06-C charge and a 07-C charge are apart at 3 m apart. What force attracts them?

Vlad [161]

Answer:

Force of 37.8 × 10^(6) N attracts the two charges

Explanation:

The force between two charges is given by

F = k*q1*q2/r²

Where q1 and q2 are 0.06 C and 0.07 C.

r is the distance between q1 and q2 which is equal to 3 m

k is a constant = 9 × 10^(9) N.m²/C²

F = (9 × 10^(9) × 0.06 × 0.07)/3²

F = 37.8 × 10^(6) N

5 0

3 years ago

The rotational speeds of four generators are listed in RPM (revolutions per minute). Arrange the generators in order based on th

artcher [175]

with the same generator, so the only factor for producing the slectric field is only the speed. The faster the rotational speed of the generator the greater it produce electric field. So the sequence is 3000 rpm < 3200 rpm < 3400 rpm < 3600 rpm

4 0

3 years ago

Read 2 more answers

A strong lightning bolt transfers an electric charge of about 16 C to Earth (or vice versa). How many electrons are transferred?

zzz [600]

Answer:

Number of electrons, $n=9.98\times 10^{19}$

Explanation:

A strong lightning bolt transfers an electric charge of about 16 C to Earth, q = 16 C

We need to find the number of electrons that transferred. Let there are n electrons transferred. It is given by using quantization of electric charge as :

q = ne

$n=\dfrac{q}{e}$

e is elemental charge

$n=\dfrac{16}{1.602\times 10^{-19}}$

$n=9.98\times 10^{19}$

So, there are $9.98\times 10^{19}$ electrons that gets transferred. Hence, this is the required solution.

3 0

3 years ago