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Ksju [112]
2 years ago
6

You probably noticed that the simulation returned varying values for the magnetic field. What other source(s) of error could occ

ur from the simulation
Physics
1 answer:
romanna [79]2 years ago
5 0

Physical and chemical laboratory experiments include three primary sources of error: systematic error, random error and human error. this simulation shows systematic error.

Systematic error applies to repeated measuring of the same object under repeated conditions of measurement. The amount of the error value is either positive or negative; which is called the fixed system error in laboratory experiments and laboratory tests.

Human error in laboratory experiments and lab tests primarily refers to the mistake in physical and chemical inspection phase caused by the factors of the inspector.

Random error is error caused by unknown factors. This error poses erratic changes at random, primarily due to a variety of small, independent, and accidental factors. The random error is atypical from the surface.

Learn more about systematic error here-

brainly.com/question/14149934

#SPJ4

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calculate the diameter of a silver wire of length 75cm , which is extended by 1.85mm when a 10kg mass is suspended from it's end
sdas [7]

Answer:0.8\ mm

Explanation:

Given

length of wire l=75\ cm

change in length \Delta l=1.85\ mm

mass of wire m=10\ kg

Young's modulus for silver E=7.9\times 10^{10}\ N/m^2

load on wire F=mg

F=10\times 9.8=98\ kg

change in length is given by

\Delta l=\dfrac{Pl}{AE}

Where A=area of cross-section

A=\dfrac{Pl}{\Delta lE}

A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}

A=\dfrac{73.5}{14.615\times 10^{7}}

A=5.029\times 10^{-7}\ m^2

also wire is the shape of cylinder so cross-section is given by

A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2

\Rightarrow d^2=\dfrac{5.029\times 10^{-7}\times 4}{\pi }

\Rightarrow d^2=64.02\times 10^{-8}

\Rightarrow d=8\times 10^{-4}\ m

\Rightarrow d=0.8\ mm

4 0
3 years ago
Analyze at the image below and answer the question that follows.
Rudiy27

the correct answer is c.

8 0
3 years ago
Read 2 more answers
Helpppp!!!ASAP!! THANK YOUUUU!
mario62 [17]

Answer:

F = 9.675Hz

Explanation:

pls for certain reasons let us make

  • wavelength = $
  • frequency = F
  • V = velocity

3 loops : 6$/4 = L

6$/4 = 2

$ = 4/3 = 1.333

V = F x $

F = V/$

F = 12.9/1.333 = 9.675Hz

F = 9.675Hz

4 0
3 years ago
Longitudinal waves cannot travel through a vacuum. True False
JulsSmile [24]
FALSE <span>Only electromagnetic </span>waves<span> can </span>travel through a vacuum<span>; mechanical </span>waves<span> such as sound </span>waves<span> require a particle-interaction to transport their energy. There are no particles in a </span>vacuum<span>. </span>Waves<span> are either </span>longitudinal<span> or transverse.
</span>Hoped i helped   :):)
4 0
3 years ago
A particle whose speed is 50 m/sec moves along the line from A(2,1) to B (9,25)
WINSTONCH [101]

First, calculate for the distance between the given points A and B by using the equation,

<span>                                                D = sqrt ((x2 – x1)2 + (y2 – y1)2)</span>

 

Substitute the known values:

<span>                                                D = sqrt((9 – 2)2 + (25 – 1)2)</span>

<span>                                                D = 25 m</span>

 

I assume the unknown here is the time it would require for the particle to move from point A to B. This can be answered by dividing the calculated distance by the speed given above.

<span>                                                t = (25 m)/ (50 m/s) = 0.5 s</span>

 

<span>Thus, it will take 0.5s for the particle to complete the route. </span>

3 0
3 years ago
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