Answer:
0.07973 moles of O2 gas were produced
2.66 atm
Explanation:
Using the ideal gas equation
PV =nRT
P =pressure = 2.9 atm
V= volume = 720 mL = 720mL/1000= 0.72 L
n = number of moles = ?
R = the gas constant = 0.0821 atm L/(mol K)
T = temperature in Kelvin = 319 K
make n subject of the formula
n =PV/RT
n = 2.9 atm x 0.72 L / 0.0821 atm L/(mol K) x 319K = 0.07973 moles of O2 gas were produced
Pnew = atm?
P = nRT/V
= 0.07973 x 0.0821 atm L/(mol K) x 293K/0.72 L = 2.66 atm
Answer:
Explanation:
Let's use Shockley ideal diode equation which relates the current intensity and the potential difference:
Where:
Thermal voltage at any temperature it is a known constant defined by:
Where:
(a)
Using the data provided:
(b)
Using the data provided and Shockley ideal diode equation
(c) Let's isolate from Shockley ideal diode equation:
Finally, using the data provided:
Answer:
Q=260.96W/m
Explanation:
you should raise the heat transfer equation between the inner part of the tube and the outer part taking into account the convection and conduction resistances
as they are asking us for the heat per unit length, then the conduction and convection resistances are like this
Rh=1/(hDpi)
Rc=ln(De/Di)/2piK
I attached the complete procedure