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Sedaia [141]
3 years ago
14

Which philosopher suggested that the mind and body are separate but that a link exists between them?

Physics
2 answers:
hammer [34]3 years ago
7 0
<span>René Descartes suggests this.</span>
ella [17]3 years ago
3 0
The philosopher that suggested that the mind and body are separate but that a link exists between them is René Descartes<span>.</span>
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After hearing about an accident on his normal route, Mr. Gujral checks for alternate routes to get to work. What type of circuit
shtirl [24]

Answer:

C

Explanation:

a parallel circuit because there is more than one path

3 0
3 years ago
Give me fun facts, the most fun fact will get brainly Est (i like animals)
swat32

Answer:

here are some fun facts lol

Dolphins sleep with one eye open

Hot water will turn into ice faster than cold water.

A crocodile cannot stick its tongue out

It is physically impossible for pigs to look up into the sky

Grapes light on fire in the microwave

McDonald's once created bubblegum-flavored broccoli.

It's impossible to sneeze with your eyes open.

High Heels Were Originally Men's Shoes

The strongest muscle in the body is the tongue.

While they are hibernating, bears do not urinate

Gummy bears were originally called "dancing bears."

Explanation:

3 0
2 years ago
Read 2 more answers
A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 5t3 + 6, where x and y are in m
ArbitrLikvidat [17]

Answer:

<h2>206.67N</h2>

Explanation:

The sum of force along both components x and y is expressed as;

\sum Fx = ma_x  \ and \ \sum Fy = ma_y

The magnitude of the net force which is also known as the resultant will be expressed as R =\sqrt{(\sum Fx)^2 + (\sum Fx )^2}

To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.

Given the position of the object along the x-component to be x = 6t² − 4;

a_x = \frac{d^2 x }{dt^2}

a_x = \frac{d}{dt}(\frac{dx}{dt} )\\ \\a_x = \frac{d}{dt}(6t^{2}-4  )\\\\a_x = \frac{d}{dt}(12t  )\\\\a_x = 12m/s^{2}

Similarly,

a_y = \frac{d}{dt}(\frac{dy}{dt} )\\ \\a_y = \frac{d}{dt}(5t^{3} +6 )\\\\a_y = \frac{d}{dt}(15t^{2}   )\\\\a_y = 30t\\a_y \ at \ t= 2.15s; a_y = 30(2.15)\\a_y = 64.5m/s^2

\sum F_x = 3.15 * 12 = 37.8N\\\sum F_y = 3.15 * 64.5 = 203.18N

R = \sqrt{37.8^2+203.18^2}\\ \\R = \sqrt{1428.84+41,282.11}\\ \\R = \sqrt{42.710.95}\\ \\R = 206.67N

Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N

7 0
3 years ago
If you fall from a building onto a net which extends the time of impact by 10 times, what happens to the force you experience?
zubka84 [21]

Answer:

A larger impulse. A 1-kg ball has twice as much speed as a 10-kg ball.

Explanation:

6 0
3 years ago
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