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Anuta_ua [19.1K]
2 years ago
15

The current atmospheres of the terrestrial planets were formed when the planets formed

Physics
1 answer:
Alexus [3.1K]2 years ago
6 0
A secondary atmosphere<span> is an </span>atmosphere<span> of a </span>planet<span> that did not form by </span>accretion<span> during the formation of the planet's </span>star<span>. A secondary atmosphere instead forms from internal </span>volcanic<span> activity, or by accumulation of material from </span>comet<span> impacts. It is characteristic of </span>terrestrial planets<span>, which includes the other terrestrial planets in the </span>Solar System<span>: </span>Mercury<span>, </span>Venus<span>, and </span>Mars<span>. Secondary atmospheres are relatively thin compared to </span>primary atmospheres<span> like </span>Jupiter's.<span> Further processing of a secondary atmosphere, for example by the processes of </span>biological life<span>, can produce a </span>tertiary atmosphere<span>, such as that of </span>Earth<span>.</span>
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A sled starts off with an initial velocity of 8 m/s and slows down to 2 m/s after 3 seconds. What was its acceleration?
melomori [17]

Answer:

-2m/s

Explanation:

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2 years ago
What are the similarities between strong nuclear force and weak nuclear force
Artemon [7]
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The visible surface of the Sun, which is also the deepest layer we can see with our eyes, is in which region of the Sun?
Nina [5.8K]
It is the photosphere
5 0
3 years ago
Bob rides his bike with a constant speed of 10 miles per hour. How long will he take to travel a distance of 15 miles?
ICE Princess25 [194]

{\underline{\pink{\textsf{\textbf{ Answer : }}}}}

➡ 150hrs.

{\underline{\pink{\textsf{\textbf{Explanation : }}}}}

➡ Time = distance × speed

➡ Time = 15*10

➡ Time = 150hrs ans.

7 0
2 years ago
A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2. Compu
boyakko [2]

Answer:

0.42 m/s²

Explanation:

r = radius of the flywheel = 0.300 m

w₀ = initial angular speed = 0 rad/s

w = final angular speed = ?

θ = angular displacement = 60 deg = 1.05 rad

α = angular acceleration = 0.6 rad/s²

Using the equation

w² = w₀² + 2 α θ

w² = 0² + 2 (0.6) (1.05)

w = 1.12 rad/s

Tangential acceleration is given as

a_{t} = r α = (0.300) (0.6) = 0.18 m/s²

Radial acceleration is given as

a_{r} = r w² = (0.300) (1.12)² = 0.38 m/s²

Magnitude of resultant acceleration is given as

a = \sqrt{a_{t}^{2} + a_{r}^{2}}

a = \sqrt{0.18^{2} + 0.38^{2}}

a = 0.42 m/s²

8 0
3 years ago
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