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3 years ago

The current atmospheres of the terrestrial planets were formed when the planets formed

1 answer:

6 0

A secondary atmosphere is an atmosphere of a planet that did not form by accretion during the formation of the planet's star. A secondary atmosphere instead forms from internal volcanic activity, or by accumulation of material from comet impacts. It is characteristic of terrestrial planets, which includes the other terrestrial planets in the Solar System: Mercury, Venus, and Mars. Secondary atmospheres are relatively thin compared to primary atmospheres like Jupiter's. Further processing of a secondary atmosphere, for example by the processes of biological life, can produce a tertiary atmosphere, such as that of Earth.

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The graphic organizer above shows that the properties of waves are influenced by the energy of waves. Name 2 properties of waves

Stells [14]

Amplitude: the height of the wave, measured in meters
Wavelength: the distance between adjacent crests, measured in meters

3 0

2 years ago

Help with these please someone?

DIA [1.3K]

Answer:

8. 2.75·10^-4 s^-1

9. No, too much of the carbon-14 would have decayed for radiation to be detected.

Explanation:

8. The half-life of 42 minutes is 2520 seconds, so you have ...

1/2 = e^(-λt) = e^(-(2520 s)λ)

ln(1/2) = -(2520 s)λ

-ln(1/2)/(2520 s) = λ ≈ 2.75×10^-4 s^-1

___

9. Reference material on carbon-14 dating suggests the method is not useful for time periods greater than about 50,000 years. The half-life of C-14 is about 5730 years, so at 65 million years, about ...

6.5·10^7/5.73·10^3 ≈ 11344

half-lives will have passed. Whatever carbon 14 may have existed at the time will have decayed completely to nothing after that many half-lives.

7 0

3 years ago

The aorta is the main artery from the heart. a typical aorta has an inside diameter of 1.8 cm and carries blood at speeds of up

defon

Answer:

Explanation:

Volume per unit time flowing will be conserved

a₁v₁ = a₂ v₂

π r₁² x v₁ = π r₂² x v₂

(0.9 x 10⁻²)² x .35 = ( .45 x 10⁻² )² x v₂

v₂ = 1.4 m / s

3 0

3 years ago

A 1.2 kg ball drops vertically onto a floor from a height of 32 m, and rebounds with an initial speed of 10 m/s.

iren [92.7K]

Explanation:

Given that,

Mass of the ball, m = 1.2 kg

Initial speed of the ball, u = 10 m/s

Height of the floor from ground, h = 32 m

(a) Let v is the final speed of the ball. It can be calculated using the conservation of energy as :

$\dfrac{1}{2}mv^2=mgh$

$v=\sqrt{2gh}$

$v=\sqrt{2\times 9.8\times 32}$

v = -25.04 m/s (negative as it rebounds)

The impulse acting on the ball is equal to the change in momentum. It can be calculated as :

$J=m(v-u)$

$J=1.2\times (-25.04-10)$

J = -42.048 kg-m/s

(b) Time of contact, t = 0.02 s

Let F is the average force on the floor from by the ball. Impulse acting on an object is given by :

$J=\dfrac{F}{t}$

$F=J\times t$

$F=42.048\times 0.02$

F = 0.8409 N

Hence, this is the required solution.

5 0

2 years ago

A plane rises from take-off and flies at an angle of 5 degrees5° with the horizontal runway. When it has gained 800800 feet, f

dedylja [7]

Answer:

$distance=9188149.567feet$

Explanation:

Given Data

Angle α=5°

height h=800800 feet

To find

Distance r

Solution

As we Know that

$Sin\alpha =(\frac{Perpendicular}{hypotenuse} )\\Sin\alpha =\frac{h}{r}\\ r=\frac{h}{Sin\alpha}\\ r=\frac{800800feet}{Sin(5^{o} )}\\ r=9188149.567feet$

4 0

3 years ago