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Anuta_ua [19.1K]
3 years ago
15

The current atmospheres of the terrestrial planets were formed when the planets formed

Physics
1 answer:
Alexus [3.1K]3 years ago
6 0
A secondary atmosphere<span> is an </span>atmosphere<span> of a </span>planet<span> that did not form by </span>accretion<span> during the formation of the planet's </span>star<span>. A secondary atmosphere instead forms from internal </span>volcanic<span> activity, or by accumulation of material from </span>comet<span> impacts. It is characteristic of </span>terrestrial planets<span>, which includes the other terrestrial planets in the </span>Solar System<span>: </span>Mercury<span>, </span>Venus<span>, and </span>Mars<span>. Secondary atmospheres are relatively thin compared to </span>primary atmospheres<span> like </span>Jupiter's.<span> Further processing of a secondary atmosphere, for example by the processes of </span>biological life<span>, can produce a </span>tertiary atmosphere<span>, such as that of </span>Earth<span>.</span>
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which of these types of radiation do you suppose we should fear the most if administered internally? •gamma rays •neutrons •alph
4vir4ik [10]
Alpha particles, because they are the heaviest ones (helium nuclei) and will travel around the body.
4 0
3 years ago
11) A sled is initially given a shove up a frictionless 35º incline. It reaches a maximum height of 2.5
Andrej [43]

Answer:

7 m/s

Explanation:

To solve this problem you must use the conservation of energy.

K1 +U1=K2+U2

That math speak for, initial kinetic energy plus initial potential energy equals final kinetic energy plus final potential energy.

The initial PE (potential energy) is 0 because it hasn't been raised in the air yet. The final KE (kinetic energy) is 0 because it isn't moving. This gives the following:

KE1= \frac{1}{2}mv^{2}}

PE2=mgh

K1=U2

\frac{1}{2} mv^{2} =mgh

Solve for v

v=\sqrt{2gh}

Input known values and you get 7 m/s.

5 0
3 years ago
Interchangeably means​
ryzh [129]

Answer:

Interchangeable is something that can be used in the same manner as something else without any important differences.

or in a more simple way

something that can be exchange

For example when two sweaters look almost the same and you could easily wear either one with a particular skirt, this is an example of when the sweaters can be worn interchangeably.

3 0
3 years ago
Read 2 more answers
1.
ivolga24 [154]

Answer:

(C) 15 Feet

Explanation:

You must park at lest 15 Feet away from a fire hydrant.

If you disobey this law, you could be fined up to $115 dollars.

7 0
3 years ago
Read 2 more answers
A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of
balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

f=\mu N

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, N=mg

∴ f=\mu mg=0.490\times 90\times 9.8=432.18\ N

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

W=-fd=-432.18d

Now, change in kinetic energy is given as:

\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J

Therefore, from work-energy theorem,

W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m

Hence, the skater covers a distance of 15 m before stopping.

7 0
3 years ago
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