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Anuta_ua [19.1K]
3 years ago
15

The current atmospheres of the terrestrial planets were formed when the planets formed

Physics
1 answer:
Alexus [3.1K]3 years ago
6 0
A secondary atmosphere<span> is an </span>atmosphere<span> of a </span>planet<span> that did not form by </span>accretion<span> during the formation of the planet's </span>star<span>. A secondary atmosphere instead forms from internal </span>volcanic<span> activity, or by accumulation of material from </span>comet<span> impacts. It is characteristic of </span>terrestrial planets<span>, which includes the other terrestrial planets in the </span>Solar System<span>: </span>Mercury<span>, </span>Venus<span>, and </span>Mars<span>. Secondary atmospheres are relatively thin compared to </span>primary atmospheres<span> like </span>Jupiter's.<span> Further processing of a secondary atmosphere, for example by the processes of </span>biological life<span>, can produce a </span>tertiary atmosphere<span>, such as that of </span>Earth<span>.</span>
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Please need help fast
iVinArrow [24]

(a) See graph in attachment

The appropriate graph to draw in this part is a graph of velocity vs time.

In this problem, we have a horse that accelerates from 0 m/s to 15 m/s in 10 s.

Assuming the acceleration of the horse is uniform, it means that the velocity (y-coordinate of the graph) must increase linearly with the time: therefore, the velocity-time graph will appear as a straight line, having the final point at

t = 10 s

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(b) 1.5 m/s^2

The average acceleration of the horse can be calculated as:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time interval

In this problem,

u = 0

v = 15 m/s

t = 10 s

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(c) 75 m

For a uniformly accelerated motion, the distance travelled can be calculated by using the suvat equation:

s=ut+\frac{1}{2}at^2

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s is the distance travelled

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t is the time interval

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u = 0

t = 10 s

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Substituting,

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(d) See attached graphs

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x=ut+\frac{1}{2}at^2

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a=1.5 m/s^2 (calculated in part b)

therefore, the graph acceleration vs time will show a flat line at a constant value of 1.5 m/s^2.

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