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sergiy2304 [10]
2 years ago
12

How much energy is required to melt 20 g of water starting at 0 o C?

Chemistry
1 answer:
Keith_Richards [23]2 years ago
6 0

The energy required to melt 20 g of water (ice) starting at 0° C is 6680 J.

<h3>What is Heat?</h3>

Heat is a form of energy that is possessed by a system by virtue of its temperature. Its unit is Joule.

Enthalpy is the amount of the heat content of a system.

<h3>What is Heat Capacity?</h3>

It is the amount of heat required to increase the temperature of a system by 1° C. It is an extensive property. Its unit is J/°C

Heat Capacity is given by

c= \frac{q}{\Delta T}

where q = heat required

\Delta T = change in temperature

Enthalpy of Fusion is the enthalpy change when 1 mole of a solid substance changes into its liquid state at its melting point.

Here, water in solid form (ice) melts into liquid form at 0°C

H_{2} O (s) \rightarrow H_{2} O(l) \\\Delta H_{fus } =334Jg^-^1

We know,

\Delta H = \frac{m}{q}\\

where m =  given mass

q = heat required

q = \Delta H \times m

q = 334 Jg^-^1 x 20 g

    = 6680 J

Thus, the heat required to melt 20 g of water at 0°C is 6680 J

Learn more about Enthalpy:

brainly.com/question/14047927

#SPJ1

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kodGreya [7K]

"Charles Law" is the relationship between "volume-temperature" (V ∝ T).

<u>Explanation</u>:  

Charles Law is basically volume-temperature relationship (V ∝ T). French scientist “Jacques Charles” in 1787 studied effect of temperature on the volume of gases at constant pressure, which described how gases manage to expand when heated. Law stated as “At constant pressure, the volume of a given "mass" of a gas decreases or increases by 1/273 of its volume at 0^{\circ} \mathrm{C} for each one degree rise or fall in temperature”. Formula derived from law is as follows: \mathbf{V}_{\mathbf{t}}=\mathbf{V}_{0}[\mathbf{1}+\mathbf{t} / \mathbf{2} 7 \mathbf{3}] here {V}_{0} is volume of given mass of a gas at 0^{\circ} \mathrm{C}, {V}_{t} is its volume at any temperature t^{\circ} \mathrm{C}. Application of Charles law is hot air balloons.

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3 years ago
6. 5.50 x 10- molecules of carbon dioxide to moles.
sergeinik [125]
1.24973017189471 is probably the answer to your equation
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3 years ago
Draw the structure(s) of the major organic product(s) of the following reaction. 1. lithium diisopropylamide / hexane 2. 1 eq. C
Jobisdone [24]

Answer:

See explanation below

Explanation:

You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.

Now let's analyze what is happening in the reaction so we can predict the final product.

We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.

Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.

Hope this helps

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3 years ago
PLEASE HELP ME ILL GIVE BRAINLIEST IF YOU EXPLAIN UR ANSWER
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The contraction of the triceps muscle causes the arm to flex. The contraction of the triceps muscle causes the arm to extend. When added to the force of the biceps contracting it provides extra force to the ball.

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5 0
3 years ago
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A wooden artifact from a Chinese temple has a 14C activity of 42.8 counts per minute as compared with an activity of 58.2 counts
Arlecino [84]

Answer : The age of the artifact is, 2.54\times 10^3\text{ years}

Explanation :

Half-life = 5715 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{5715\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time taken to decay.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken by sample = ?

a = initial activity of the reactant  = 58.2 counts per minute

a - x = activity left after decay process  = 42.8 counts per minute

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{58.2}{42.8}

t=2540.5\text{ years}=2.54\times 10^3\text{ years}

Therefore, the age of the artifact is, 2.54\times 10^3\text{ years}

4 0
3 years ago
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