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iren2701 [21]
3 years ago
7

The phase change from liquid water to water vapor involves more energy than the phase change from water vapor to liquid water. s

elect one:
a. true
b. false
Chemistry
1 answer:
rjkz [21]3 years ago
7 0
Greetings!

I believe the answer is true.
While precipitation does require a lot of energy, evaporation takes longer, and requires more energy from heat, whereas precipitation doesn't really require any.

Hope this helps you!

>>DL<<
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The solubility of substance (Z) is 40g/100ml of water at 25°C. A)Can you
anyanavicka [17]

Answer:

No, It would be a unsaturated solution

Explanation:

The solubility of a compound gives us information about how a compound may dissolve or not in a determinate solvent.

In this case we have Z, which in 25 °C the solubility of this compound is 40g/100 mL water. This means that if we have 60 g of Z and try to dissolve it in 100 mL of water, only 40 g of Z will solve and the remaining 20 g will be in the water as precipitate or remaining solid.

Now if you just put 40 g of Z in 100 mL water, it will dissolve completely in water, and in this case, we have a saturated solution. A saturated solution is when you dissolve a determinated quantity of a solute in a determinated quantity of solvent, without remaining of solid or excess of solvent.

According to this explanation, we now have 120 g of Z. To make a saturated solution of Z with this quantity, well, let's do math. If 40 g dissolves in 100 mL, then 80 g would be 200 mL and 120 g would have to be 300 mL of water. But in this case, we have 450 mL of water, we have more than 300 mL, an excess of water, so, the 120 g will dissolve but it's dissolved in more than the needed quantity to be a saturated solution, therefore, we have an unsaturated solution of Z (more solvent than the needed).

Hope this helps.

8 0
3 years ago
Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but
alukav5142 [94]

Answer:

a) For nicotine, the protonated form is the present in stomach.

b) For caffeine, the neutral base form is the present in stomach.

c) For Strychinene, the protonated form is the present in stomach.

d) For quinine, the protonated form is the present in stomach.

Explanation:

In a basic dissociation for molecules with basic nitrogen, the equilibrium is:

A + H₂O ⇄ AH⁺ + OH⁻

<em>Where A is neutral base and AH⁺ is protonated form</em>

The basic dissociation constant, kb, is:

K_{b} = \frac{[AH^+][OH^-]}{[A]}

As pH in stomach is 2,5:

[OH] =10^{-[14-pH]}

[OH] = 3,16x10⁻¹² M

Thus:

\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]} <em>(1)</em>

Using (1) it is possible to know if you have the neutral base or the protonated form, thus:

(a) nicotine Kb = 7x10^-7

\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}

\frac{7x10^{-7}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}

221359 = \frac{[AH^+]}{[A]}

[AH⁺}>>>>[A]

For nicotine, the protonated form is the present in stomach

(b) caffeine,Kb= 4x10^-14

\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}

\frac{4x10^{-14}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}

0,0127 = \frac{[AH^+]}{[A]}

[AH⁺}<<<<[A]

For caffeine, the neutral base form is the present in stomach

(c) strychnine Kb= 1x10^-6

\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}

\frac{1x10^{-6}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}

314456 = \frac{[AH^+]}{[A]}

[AH⁺}>>>>[A]

For Strychinene, the protonated form is the present in stomach

(d) quinine, Kb= 1.1x10^-6

\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}

\frac{1,1x10^{-6}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}

347851= \frac{[AH^+]}{[A]}

[AH⁺}>>>>[A]

For quinine, the protonated form is the present in stomach.

I hope it helps!

7 0
3 years ago
You have been given an orange liquid and told to describe its properties.
chubhunter [2.5K]

Answer:

The correct answer would be - observing with the help of five senses.

Explanation:

To find and describe the physical properties of the given substance or the solution or liquid students can observe using their five senses. By looking at the liquid one can find its state and color, by smelling students can find the odor of the sample, by touching it one can observe and describe the texture.

Fluidity can also be measure by the touch if the solution is viscous or free-floating. By using a thermometer and using a graduated cylinder one can find the temperature at room temperature and the weight of substance respectively.

5 0
4 years ago
If you lift an object that weighs 13 pounds through a distance of 3 feet, you have done foot-pounds of work.
Katyanochek1 [597]
The answer to your statement is true 

3 0
3 years ago
Read 2 more answers
2.50 L of gas originally at 50 K is warmed to 80 K. If the pressure remains constant, which gas law needs to be used to find the
Brilliant_brown [7]

Answer:

A

Explanation:

You want an equation that includes both V and T. Charles' Law states that V =kT or V₁/T₁ = V₂/T₂, so this is the best formula to use.

B: The Combined Gas Law is p₁V₁/T₂ = p₂V₂/T₂ will work, but it's overkill for the situation. You can assume any constant value for the pressure, and it will cancel from each side of the equation,

C is wrong. Boyle's Law is p₁V₁ = p₂V₂. It does not include the temperature.

D is wrong. Gay-Lussac's Law is p₁/T₂ = p₂/T₂. It does not include the volume.

7 0
3 years ago
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