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alekssr [168]
2 years ago
14

Heteropoly tungstate supported on tantalum oxide: A highly active acid catalyst for the selective conversion of fructose to 5-hy

droxy methyl furfural
Chemistry
1 answer:
horsena [70]2 years ago
4 0

TPA catalysts based on tantalum oxide (Ta2O5) were produced and studied by FT-infrared, X-ray diffraction, Laser Raman, and temperature programmed ammonia desorption.

<h3>How did Lewis acidity induced heteropoly tungstate catalysts?</h3>

Heteropoly tungstate was synthesised and spread over tin oxide containing tantalum ions in its secondary structure. Different spectroscopic approaches were used to estimate the physical and chemical characteristics of the produced compounds. The inclusion of Ta ions in heteropoly tungstate resulted in the formation of new Lewis acidic sites. These samples were evaluated for their ability to catalyse the conversion of fructose to 5-ethoxymethylfurfural (EMF) and the selective etherification of 5-hydroxymethylfurfural (HMF) with ethanol. The catalyst with 30% active component on SnO2 had the greatest HMF etherification activity, yielding 90% 5-ethoxymethylfurfural in 45 minutes. The catalysts were also capable of converting fructose into EMF in a single pot with a 68% yield.

learn more about lewis acidity refer:

brainly.com/question/15220646

#SPJ4

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In basic terms only some substances can make a solutions others are refered to as insoluble as they can't be seperated in water or another solvent. In actuality however all ionic compounds (compounds that are composed of ions) are at least somewhat soluble, but don't dissociate well at all in some solvents. 

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5 0
3 years ago
1. Write the name of any four chemical preservatives mixed with readymade<br>Food.​
Inga [223]

Answer:

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4 0
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Describe three different scenarios where a chemical process or reaction shows an increase in entropy.
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4 0
3 years ago
What is the concentration (m) of sodium ions in 4.57 l of a 2.35 m na3p solution?
Leokris [45]
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5 0
3 years ago
Read 2 more answers
You wish to prepare a buffer consisting of acetic acid and sodium acetate with a total acetic acetate plus acetate concentration
vovangra [49]

<u>Ans: Acetic acid = 90.3 mM and Sodium acetate = 160 mM</u>

Given:

Acetic Acid/Sodium Acetate buffer of pH = 5.0

Let HA = acetic acid

A- = sodium acetate

Total concentration [HA] + [A-] = 250 mM ------(1)

pKa(acetic acid) = 4.75

Based on Henderson-Hasselbalch equation

pH = pKa + log[A-]/[HA]

[A-]/[HA] = 10^(pH-pKa) = 10^(5-4.75) = 10^0.25 = 1.77

[A-] = 1.77[HA] -----(2)

From (1) and (2)

[HA] + 1.77[HA] = 250 mM

[HA] = 250/2.77 = 90.25 mM

[A-] = 1.77(90.25) = 159.74 mM



7 0
4 years ago
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