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alekssr [168]
1 year ago
14

Heteropoly tungstate supported on tantalum oxide: A highly active acid catalyst for the selective conversion of fructose to 5-hy

droxy methyl furfural
Chemistry
1 answer:
horsena [70]1 year ago
4 0

TPA catalysts based on tantalum oxide (Ta2O5) were produced and studied by FT-infrared, X-ray diffraction, Laser Raman, and temperature programmed ammonia desorption.

<h3>How did Lewis acidity induced heteropoly tungstate catalysts?</h3>

Heteropoly tungstate was synthesised and spread over tin oxide containing tantalum ions in its secondary structure. Different spectroscopic approaches were used to estimate the physical and chemical characteristics of the produced compounds. The inclusion of Ta ions in heteropoly tungstate resulted in the formation of new Lewis acidic sites. These samples were evaluated for their ability to catalyse the conversion of fructose to 5-ethoxymethylfurfural (EMF) and the selective etherification of 5-hydroxymethylfurfural (HMF) with ethanol. The catalyst with 30% active component on SnO2 had the greatest HMF etherification activity, yielding 90% 5-ethoxymethylfurfural in 45 minutes. The catalysts were also capable of converting fructose into EMF in a single pot with a 68% yield.

learn more about lewis acidity refer:

brainly.com/question/15220646

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Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The
yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of N_2 = 8.00 atm

The partial pressure of O_2 = 5.00 atm

K_p = 0.0025

The balanced equilibrium reaction is,

                               N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

Initial pressure     8.00      5.00            0

At eqm.               (8.00-x) (5.00-x)        2x

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}

Now put all the values in this expression, we get :

0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}

By solving the terms, we get:

x=0.15atm

The equilibrium partial pressure of N_2 = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of N_2 is 7.8 atm.

3 0
4 years ago
A steel tank contains carbon dioxide at a pressure of 13.0 atm when the temperature is 34oC. What will be the internal gas press
morpeh [17]

Answer:

D. 15.8atm

Explanation:

Given parameters:

Initial pressure = 13atm

Initial temperature  = 34°C = 34 + 273  = 307K

Final temperature  = 100°C = 100 + 273  = 373K

Unknown:

Final pressure  = ?

Solution:

To solve this problem, we apply a derivation of the combined gas law taking the volume as a constant.

The expression is shown mathematically below;

        \frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }

P and T pressure and temperature values

1 and 2 are initial and final states

 Insert the parameters and solve for T₂;

    \frac{13}{307}   = \frac{P_{2} }{373}  

        P₂  = 15.8atm

4 0
3 years ago
What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

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Answer:

E

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None of the above

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4 0
3 years ago
A price support is a type of _____. price fixing price floor rent control price ceiling
Oksi-84 [34.3K]
Subsidy

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4 0
3 years ago
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